Answer:
<u>y'= 5x^4 + 5^x In(5)</u>
Step-by-step explanation:
<u>Differentiate</u><u> </u><u>with </u><u>Respect</u><u> </u><u>to</u><u> </u><u>x</u>
<u>f(</u><u>x)</u><u>'</u><u>=</u><u>5</u><u>x</u><u>^</u><u>4</u><u> </u><u>+</u><u> </u><u>In(</u><u>5</u><u>^</u><u>x</u><u>)</u>
<u>f(</u><u>x)</u><u>'</u><u>=</u><u> </u><u>5</u><u>x</u><u>^</u><u>4</u><u> </u><u>+</u><u> </u><u>x </u><u>In(</u><u>5</u><u>)</u>
<u>with </u><u>respect</u><u> </u><u>to </u><u>x,</u><u> </u><u>we </u><u>have</u>
<u>y'=</u><u> </u><u>5</u><u>x</u><u>^</u><u>4</u><u> </u><u>+</u><u> </u><u>y </u><u>In(</u><u>5</u><u>)</u>
<u>y'=</u><u> </u><u>5</u><u>x</u><u>^</u><u>4</u><u> </u><u>+</u><u> </u><u>5</u><u>^</u><u>x</u><u> </u><u>In(</u><u>5</u><u>)</u>
That is false, miss. It IS the radius.
Answer: 61,750 miles
Step-by-step explanation:
Given : The p-value of the tires to outlast the warranty = 0.96
The probability that corresponds to 0.96 from a Normal distribution table is 1.75.
Mean :
Standard deviation :
The formula for z-score is given by : -
Hence, the tread life of tire should be 61,750 miles if they want 96% of the tires to outlast the warranty.
Answer:
6(3h+5k)
Step-by-step explanation:
18h+30k
Factors of 18:
1, 2, 3, 6, 9, 18
Factors of 30:
1, 2, 3, 5, 6, 10, 15, 30
GCF of 18 and 30: 6
18h+30k = 6(3h+5k)
Check your answer:
6(3h+5k)
6(3h) + 6(5k)
18h + 30k
Hope this helps!
If anything is above 5 it will round up