All categories

3 years ago

A number t is less than 7

Mathematics

2 answers:

ICE Princess25 [194]3 years ago

8 0

Answer:

6 or 5 or 4...........

Step-by-step explanation:

kotegsom [21]3 years ago

3 0

Answer:

x=N :x<7

Step-by-step explanation:

123456

hope it's helpful

You might be interested in

Write the set by listing its elements.

IceJOKER [234]

Step-by-step explanation:

set o= o

set t= t

those are the set of letters used to form the set

7 0

3 years ago

Simplify i^41 (please help me)

ira [324]

Answer:

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

A) prove that MQX is congruent to MRY

Viktor [21]

Answer:

Side MQ is similar to side MR.

- This is because since M is the mid point of QR, both MQ and MR are half of QR.

Angle MXQ and MYR are 90°

Sides QX and RY are similar.

- This is because angle X and Y are 90° and MQ and MR are equal.

∴ MQX is congruent to MRY.

7 0

3 years ago

Please consider the following values for the variables X and Y. Treat each row as a pair of scores for the variables X and Y (wi

Studentka2010 [4]

Answer:

The Pearson's coefficient of correlation between the is 0.700.

Step-by-step explanation:

The correlation coefficient is a statistical degree that computes the strength of the linear relationship amid the relative movements of the two variables (i.e. dependent and independent).It ranges from -1 to +1.

The formula to compute correlation between two variables <em>X</em> and <em>Y</em> is:

$r(X, Y)=\frac{Cov(X, Y)}{\sqrt{V(X)\cdot V(Y)}}$

The formula to compute covariance is:

$Cov(X, Y)=n\cdot \sum XY-\sum X \cdot\sum Y$

The formula to compute the variances are:

$V(X)=n\cdot\sum X^{2}-(\sum X)^{2}\\V(Y)=n\cdot\sum Y^{2}-(\sum Y)^{2}$

Consider the table attached below.

Compute the covariance as follows:

$Cov(X, Y)=n\cdot \sum XY-\sum X \cdot\sum Y$

$=(5\times 165)-(30\times 25)\\=75$

Thus, the covariance is 75.

Compute the variance of X and Y as follows:

$V(X)=n\cdot\sum X^{2}-(\sum X)^{2}\\=(5\times 226)-(30)^{2}\\=230\\\\V(Y)=n\cdot\sum Y^{2}-(\sum Y)^{2}\\=(5\times 135)-(25)^{2}\\=50$

Compute the correlation coefficient as follows:

$r(X, Y)=\frac{Cov(X, Y)}{\sqrt{V(X)\cdot V(Y)}}$

$=\frac{75}{\sqrt{230\times 50}}$

$=0.69937\\\approx0.70$

Thus, the Pearson's coefficient of correlation between the is 0.700.

5 0

3 years ago

In 2000, there were an estimated 5.28 million digital cable subscribers in the United States. The expected increase is 2.61 mill

STALIN [3.7K]

Answer:

Step-by-step explanation:

I am taking the practice.

3 0

3 years ago

Read 2 more answers