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3 years ago

2. A graphic designer is creating an advertisement for a tablet. She needs to enlarge the picture so that 2

Mathematics

1 answer:

trapecia [35]3 years ago

8 0

Answer:

lol the answer is 49

Step-by-step explanation:

hope this helps <3

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Help please quickly if possible

rusak2 [61]

Answer:

i dont get the question

Step-by-step explanation:

3 0

4 years ago

Solve the problem.A plane flying a straight course observes a mountain at a bearing of 35° to the right of its course. At that t

Mice21 [21]

Given:

A plane flying a straight course observes a mountain at a bearing of 35° to the right of its course.

The distance between plan and mountain is 10 km.

A short time later, the bearing to the mountain becomes 45°.

Here NM is the distance between the plane from the mountain when the second bearing is taken.

We need to find the measure of NM.

$We\text{ know that }\angle INM\text{ and }\angle\text{XNM are supplementary angles.}$

The sum of the supplementary angles is 180 degrees.

$\angle INM+\angle XNM=180^o$ $\text{Substitute }\angle XNM=45^o\text{ in the equation.}$

$\angle INM+45^o=180^o$

$\angle INM=180^o-45^o$

$\angle INM=135^o$

We know that the sum of all three angles of the triangle is 180 degrees.

$\angle INM+\angle NIM+\angle INM=180^o$ $\text{Substitute }\angle INM=135^o\text{ and }\angle NIM=35^o\text{ in the equation.}$

$135^o+35^o+\angle INM=180^o$

$170^o+\angle INM=180^o$

$\angle INM=180^o-170^o$

$\angle INM=10^o$

Consider the sine law.

$\frac{\sin N}{IM}=\frac{\sin M}{IN}=\frac{\sin I}{NM}$

Take the equation to find the measure of NM.

$\frac{\sin N}{IM}=\frac{\sin I}{NM}$ $\text{Substitute }\angle N=135^o,\angle I=35^o,\text{ and IM=10 in the equation.}$

$\frac{\sin 135^o}{10}=\frac{\sin35^o}{NM}$

$NM=\frac{\sin 35^o}{\sin 135^o}\times10$ $NM=8.11$

Hence the measure of NM is 8.1 km.

The plane is 8.1 km far from the mountain when the second bearing is taken.

5 0

1 year ago

Simplify the following expression completely, where x is greater than or equal too 0.

Dennis_Churaev [7]

First you want the numbers under the radical to be the same so you can combine like terms.

$x \sqrt{5xy^4} =x \sqrt{5x*^4y} = xy^2 \sqrt{5x}$
$\sqrt{405x^3y^4} = \sqrt{5x*81x^2y^4} =9xy^2 \sqrt{5x}$
$\sqrt{80x^3y^4} = \sqrt{5x*16x^2y^4} = 4xy^2 \sqrt{5x}$

Now add together to get $14xy^2 \sqrt{5x}$