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KATRIN_1 [288]
3 years ago
12

This is my last question anyone?

Mathematics
1 answer:
denis23 [38]3 years ago
3 0
$2 :) !!!!!!!!!!!!!!!!!!!!!!!!!
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-3(2+ k)- 6k = 6+ 3k
belka [17]

Answer:

solve for k,  k=-1

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable

6 0
3 years ago
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if the ratio of matts age to carlys age is 2/3, in ten years the ratio will be 4/5. how old is matthew?
Dima020 [189]
Matthew should be 14 yrs old
7 0
3 years ago
The volume of a gas in a container varies inversely as the pressure on the gas. If a gas has a volume of 173 cubic inches under
Kazeer [188]

Answer:

9 pounds per square inch

Step-by-step explanation:

Let V = the gas' volume and P = its pressure.  The volume of a gas in a container varies inversely with the pressure on the gas:

    V = k/P

where  k is a constant.  To find the value of k, plug in the one known point, V = 390 cubic inches when P = 7 pounds per square inch and solve for k:

    V = k/p

    390 = k/7

    390*7 = k

    2730 = k

The full equation, then, is:

    V = 2730/P

To find the volume when P = 9 pounds per square inch:

    V = 2730/9 = _____ cubic inches

4 0
4 years ago
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You weld three metal strips together that are 5.65 cm, 6.70 cm and 4.32 cm How long will the metal strip be now?
boyakko [2]
5.65 + 6.70 + 4.32 = 16.67
6 0
4 years ago
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Please use picture for the question not the writing
Alex787 [66]

\tt \: f(x) =  {x}^{2}  + 4x - 1

To complete the square, the same value needs to be added to both sides

\tt \: f(x)  +  ? =  {x}^{2}  + 4x  + ? - 1

To complete the square, Add 4 on both sides of the equation

\tt \: f(x) + 4 =  {x}^{2}  + 4x + 4 - 1

Use a²+2ab+b²=(a+b)² to factor the expression

\tt \: f(x) + 4 = (x + 2)^{2}  - 1

Move the constant to the right-hand side and change its sign

\tt \: f(x) =  {(x + 2)}^{2} - 1 - 4

Calculate the difference

\tt \: f(x) =  {(x + 2)}^{2} -5

And, We are done solving!!~

\red{ \rule{35pt}{2pt}} \orange{ \rule{35pt}{2pt}} \color{yellow}{ \rule{35pt} {2pt}} \green{ \rule{35pt} {2pt}} \blue{ \rule{35pt} {2pt}} \purple{ \rule{35pt} {2pt}}

<em>The option that corresponds our final answer is option D...</em>

7 0
3 years ago
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