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ankoles [38]
3 years ago
10

What is quadratic formula?

Mathematics
2 answers:
shusha [124]3 years ago
4 0

Answer:

The quadratic formula allows us to solve any quadratic equation that's in the form ax^2 + bx + c = 0.

Step-by-step explanation:

victus00 [196]3 years ago
4 0

Answer:

Step-by-step explanation:

You might be interested in
Which sequence follows the rule 2n + 6, where n represents the position of a term in a sequence? 6, 8, 12, 18, . . . 6, 12, 18,
melamori03 [73]

ANSWER

8, 10, 12, 14, . . .

EXPLANATION

The given rule for the sequence is :

f(n)=2n+6

The domain for a sequence is the set of natural numbers.

When n=1,

f(1)=2(1)+6=8

When n=2,

f(2)=2(2)+6=10

When n=3,

f(3)=2(3)+6=12

When n=4,

f(4)=2(4)+6=14

Therefore the sequence that follows the given rule is

8, 10, 12, 14, . . .

8 0
4 years ago
Point Q’ is the image of Q (3,-4) under a reflection across the x-axis
7nadin3 [17]

Answer:

Q' (-3,4)

Step-by-step explanation:

A reflection across the x-axis would mean that only the x value of the point would change. This means that the y value would still be 4. To find the x value, just flip it to a negative. The negative of 3 is -3

5 0
3 years ago
Read 2 more answers
HELPPPPPPPPPP MEEEEEEEEE IM TO YOUNG TO DIE
Zanzabum

Answer:

Im either gonna say, the last one or the first. Please dont hate me.

8 0
3 years ago
Read 2 more answers
How can you use an equation to make a prediction from a pattern?
Vanyuwa [196]
Upon formation of an equation from a given pattern, we know how the variables in the patter are related. Using the equation, we can find the value of one of the missing variables if the rest are known and also predict the values of the pattern at given conditions.
An example:
y = 2x + 5
if we are to predict the value of y at x = 3, we simply substitute 3 into x
y = 2(3) + 5
= 11
8 0
3 years ago
Read 2 more answers
2. Margie Spencer wants to have $100,000 in her savings account in 20 years. If her account pays 6.6% annual
WITCHER [35]

~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\dotfill & \$100000\\ P=\textit{original amount deposited}\\ r=rate\to 6.6\%\to \frac{6.6}{100}\dotfill &0.066\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{semiannually, thus two} \end{array}\dotfill &2\\ t=years\dotfill &20 \end{cases}

100000=P\left(1+\frac{0.066}{2}\right)^{2\cdot 20}\implies 100000=P(1.033)^{40} \\\\\\ \cfrac{100000}{1.033^{40}}=P\implies 27288.97\approx P

7 0
2 years ago
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