The answer is e because I look it up
        
             
        
        
        
Answer:
13x^2 - 6x -11
Step-by-step explanation:
 
        
             
        
        
        
Answer:
V = 6x²(2x - 5)
Step-by-step explanation:
Factor the dimensions, that is
24x² + 6x = 6x(4x + 1) ← common factor of 6x
x² - x = x(x - 1) ← common factor of x
The product lwh can now be written
V =  × (2x - 5) ×
 × (2x - 5) × 
Cancel the factors (4x + 1) and (x - 1) from the numerators/ denominators
V = 6x × x × (2x - 5) = 6x²(2x - 5) ← in factored form
 
 
        
                    
             
        
        
        
The number of integer values of n for which the value 4000 × (0.4)ⁿ is an integer is; 9 
<h3>How to find the integer values in algebra?</h3>
We are given the expression;
4000 × (0.4)ⁿ
This can also be expressed as;
4000 × (²/₅)ⁿ which can further be expressed in exponent form as;
(2⁵ × 5³) × (²/₅)ⁿ = 2⁽⁵ ⁺ ⁿ⁾ × 5⁽³ ⁻ ⁿ⁾
Since this expression is an integer, we need:
1) 5 + n ≥ 0 for which n ≥ -5
2) 3 - n ≥ 0 for which n ≤ 3
Taking the intersection gives;
-5 ≤ n ≤ 3
Thus;
Number of Integer Values = 3 - (-5) + 1 = 9
Read more about Integer Values at; brainly.com/question/17695139
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The would be 1 1/4
Ask me if you need me to explain