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BaLLatris [955]
3 years ago
10

The use of line symbols enables engineers/designer to express features of designed product and accurately.

SAT
1 answer:
Anna11 [10]3 years ago
4 0

Answer:

a. alphabet line

Explanation:

Technical drawings are the drawings that help in communicating the designs. These designs are the designs that provide the instruction for the manufacturing of any object. The designs are made with the help of lines and line symbols. Line symbols are termed to be alphabet of lines. They help the designers to draw the designs with accuracy. Various lines are drawn that differ in terms of thickness and darkness. These variations helps the designers to mark the design accurately.

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What is common form of water​
serg [7]

Answer:

liquid

Explanation:

the form of water has a matter of liquid

8 0
2 years ago
If a person takes 30 ml of vinegar a day and the molarity of the vinegar is 0. 84 m then how many grams of acetic acid (hc2h3o2
babunello [35]

The mass of the acetic acid is 1.512 g.

<h3 /><h3>What is Molarity?</h3>

molarity is the concentration of a substance in mol per dm³

From the question,

The number of moles contained in the 30 mL vinegar is

  • n = (0.84×30)/1000
  • n = 0.0252 mol.

the molar mass of vinegar is calculated below.

  • m.m of (HC₂H₃O₂) = [1+(12×2)+(1×3)+(16×2)]
  • m.m = (1+24+3+32]
  • m.m = 60 g/mol.

To calculate the mass of acetic acid, we use the formula below.

  • R.m = n×m.m............. Equation 1

Where

  • R.m = mass of acetic acid.

Substitute these values into equation 1

  • R.m = (0.0252×60)
  • R.m = 1.512 g.

Hence, The mass of the acetic acid is 1.512 g.

Learn more about molarity here: brainly.com/question/20383725

8 0
2 years ago
Calculate the mass of hydrogen in 57. 010 grams of ammonium hydrogen phosphate.
erastovalidia [21]

The mass of hydrogen in 57.010 g ammonium hydrogen phosphate, (NH₄)H₂PO₄ is 2.97 g  

<h3>Determination of mass of 1 mole of (NH₄)H₂PO₄ </h3>

1 mole of (NH₄)H₂PO₄ = 14 + (4×1) + (2×1) + 31 + (16×4) = 115 g

<h3>Determination of the mass of H in 1 mole of (NH₄)H₂PO₄ </h3>

Mass of H = 6H = 6 × 1 = 6 g

<h3>Determination of the mass of H in 57.010 g of (NH₄)H₂PO₄ </h3>

115 g of (NH₄)H₂PO₄ contains 6 g of H.

Therefore,

57.010 g of (NH₄)H₂PO₄ will contain = (57.010 × 6) / 115 = 2.97 g of H

Thus, 2.97 g of Hydrogen, H is present in 57.010 g of (NH₄)H₂PO₄

Learn more about mass composition:

brainly.com/question/13531044

4 0
2 years ago
10 points and will mark brainliest!
CaHeK987 [17]

A, B, B, A, B, A

Hope this helps.

3 0
3 years ago
Let p(x) be the statement x spends more than five hours every weekday in class
trapecia [35]

Answer:

p(x)= x +5

Explanation:

3 0
2 years ago
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