All categories

3 years ago

How many solutions can be found for the equation 4x - 8 - 4x = 9? (4 points)

Mathematics

1 answer:

Ksivusya [100]3 years ago

3 0

Answer:

A. Zero

Step-by-step explanation:

This would have no solution because when you try to solve the equation and simplify, the 4x's cancel out, leaving no variable and making the equation reduce to: -8=9 which is false, and therefore, this has no solution.

I hope this helps!

You might be interested in

G(t)=−(t−1) 2 +5g, left parenthesis, t, right parenthesis, equals, minus, left parenthesis, t, minus, 1, right parenthesis, squa

bija089 [108]

Answer:

average = -9

lower than 5

Step-by-step explanation:

You have the following formula:

$G(t)=-(t-1)^2+5$

to calculate the average rate of change you first calculate the derivative:

$\frac{dG}{dt}=-2(t-1)$

the interval of dG/dt for −4≤t≤5 is:

t = -4

$\frac{dG}{dt}=-2(-4-1)=10$

t = 5

$\frac{dG}{dt}=-2(5-1)=-8$

the average rate of change is :

$average\ =\ \frac{-8-10}{2}=-9$

is lower that 5

3 0

3 years ago

Is 5400 perfect square?if not how it should cames 5400 by division

kap26 [50]

Answer:

73.4846922835 = 73.5 and no it is not a perfect square 5400/100 = 54

8 0

3 years ago

1 2.2.5 Quiz: Volume

LUCKY_DIMON [66]

Answer:

12 1/2 cubic units, the formula is Lenght × Width × Hieght

6 0

3 years ago

P=2 (w+h) h the subject

UkoKoshka [18]

P=2(w+h)
remember you can do anythig to an equaotn as lng as you do it to both sides
divide both sides by 2
P/2=w+h
subtract w
(P/2)-w=h

7 0

4 years ago

Read 2 more answers

One method of slowing the growth of an insect population without using pesticides is to introduce into the population a number o

Zielflug [23.3K]

To be clear, the given relation between time and female population is an integral:
 $t = \int { \frac{P+S}{P[(r - 1)P - S]} } \,
dP$

The problem says that r = 1.2 and S = 400, therefore substituting:
 $t = \int { \frac{P+400}{P[(1.2 - 1)P - 400]}
} \, dP$ 

= $
\int { \frac{P+400}{P(0.2P - 400)} } \, dP$

In order to evaluate this integral, we need to write this rational function in a simpler way:
 $\frac{P+400}{P(0.2P - 400)} = \frac{A}{P} +
\frac{B}{(0.2P - 400)}$ 

where we need to evaluate A and B. In order to do so, let's calculate the LCD:
 $\frac{P+400}{P(0.2P - 400)} = \frac{A(0.2P -
400)}{P(0.2P - 400)} + \frac{BP}{P(0.2P - 400)}$ 

the denominators cancel out and we get:
P + 400 = 0.2AP - 400A + BP
 = P(0.2A + B) - 400A

The two sides must be equal to each other, bringing the system:
 $\left \{ {{0.2A + B = 1} \atop {-400A =
400}} \right.$ 

Which can be easily solved:
 $\left \{ {{B=1.2} \atop {A=-1}} \right.$ 

Therefore, our integral can be written as:
 $t = \int { \frac{P+400}{P(0.2P - 400)} } \,
dP = \int {( \frac{-1}{P} + \frac{1.2}{0.2P-400} )} \, dP$ 
= $- \int { \frac{1}{P} \, dP +
1.2\int { \frac{1}{0.2P-400} } \, dP$ 
= $- \int { \frac{1}{P} \, dP +
6\int { \frac{0.2}{0.2P-400} } \, dP$ 
= - ln |P| + 6 ln |0.2P - 400| + C

Now, let’s evaluate C by considering that at t = 0 P = 10000:
0 = - ln |10000| + 6 ln |0.2(10000) - 400| + C
C = ln |10000| - 6 ln |1600|
C = ln (10⁴) - 6 ln (2⁶·5²)
C = 4 ln (10) - 36 ln (2) - 12 ln (5) 
 Therefore, the equation relating female population with time requested is:
t = - ln |P| + 6 ln |0.2P - 400| + 4 ln (10) - 36 ln (2) - 12 ln (5)

8 0

3 years ago