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3 years ago

Using the segment addition postulate, find the value of x.

Mathematics

1 answer:

lyudmila [28]3 years ago

3 0

Answer:The Segment Addition Postulate. Find the length indicated. 1). H. F. G. 1. 10 ? 2) ... 9. 11. 6) Find HJ. G. J. H. I. 2. 7. 12. 7) Find EC. E. B. D. C. 16. 49. 30. 8) Find IK ... Find x. 12) AC = 22, BC = x + 14, and AB = x + 10. Find x. Solve for x. 13). N. K ... 14). S. V. T. U. 2x - 18. 4x - 29. 6. 13. Find the length indicated. 15) Find CE. B.

Step-by-step explanation:

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Evaluate. (-5)5 Enter your answer in the box.

Klio2033 [76]

Answer:

The answer is -25

Step-by-step explanation:

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3 years ago

What is an equation of the line that passes through the point (1, -2) and is parallel

Oliga [24]

Answer:

y = -6x + 4

Step-by-step explanation:

2 parallel lines should have equal slope

Rewrite 6x + y = 92

It is now y = -6x + 92. Slope is -6

So the new equation should also have -6 as the slope.

y = -6x + b

Substitute (1,-2) into this equation

-2 = -6(1) + b

-2 = -6 + b

4 = b

So equation is y = -6x + 4

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3 years ago

What is a correct name for the angle shown?

LekaFEV [45]

Answer:

Step-by-step explanation:

the angle itself is s therefore the correct answer is angle s, otherwise it would be rst going left to right, but that is not an option.

7 0

2 years ago

Read 2 more answers

Find the solution of the given initial value problem in explicit form. y' = (1 – 11x)y?, y(0) = -1 Enclose numerators and denomi

Tanya [424]

Answer:

$y(x)=-e^{x-(\frac{11*x^{2} }{2}) }$

Step-by-step explanation:

This is a separable equation. First divide both sides by y:

$\frac{dy(x)}{\frac{dx}{y(x)} } =-11x+1\\\frac{dy}{y}=(-11x+1)dx$

Integrate both sides:

$\int\ \frac{dy}{y} \ =\int\ (-11x+1) \, dx$

$log(y)=-(\frac{11*x}{2} )+x+ c_1$

Solve for y taking exp to both sides:

$y(x)=c_1*e^{x-(\frac{11*x^{2} }{2}) }$

Where $c_1$ is an arbitrary constant

Evaluating the initial condition:

$y(0)=c_1*e^{0-(\frac{11*0^{2} }{2}) } =-1$

$c_1*e^{0} =-1\\c_1*1=-1\\c_1=-1$

Finally, replacing $c_1$ in the differential equation solution:

$y(x)=-e^{x-(\frac{11*x^{2} }{2}) }$

8 0

3 years ago

The slope-intercept form given (6,-5) & perpendicular to -5x - 7y = -17.

tatuchka [14]

Answer:

$y=\dfrac{7}{5}x-\dfrac{67}{5}$

Step-by-step explanation:

Slope-intercept form of a linear equation:

$y=mx+b$

where:

m is the slope.
b is the y-intercept.

Rearrange the given equation so that it is in slope-intercept form:

$\implies -5x-7y=-17$

$\implies -7y=5x-17$

$\implies y=-\dfrac{5}{7}x+\dfrac{17}{7}$

Therefore, the slope of the given equation is -⁵/₇.

If two lines are perpendicular to each other (at right angles), the product of their slopes will be -1. Therefore, their slopes will be negative reciprocals of each other.

Therefore, the slope of the line perpendicular to the given equation is:

$\sf m=\dfrac{7}{5}$