The segment of length x bisects the chord of length 19.2.
The diameter is 24, so the radius is 12.
You have a right triangle with hypotenuse 12, and one leg 19.2/2 = 9.6
9.6^2 + x^2 = 12^2
92.16 + x^2 = 144
x^2 = 51.84
x = 7.2
Here it is given that AB || CD
< EIA = <GJB
Now
∠EIA ≅ ∠IKC and ∠GJB is ≅ ∠ JLD (Corresponding angles)
∠EIA ≅ ∠GJB then ∠IKC ≅ ∠ JLD (Substitution Property of Congruency)
∠IKL + ∠IKC 180° and ∠DLH + ∠JLD =180° (Linear Pair Theorem)
So
m∠IKL + m∠IKC = 180° ....(1)
But ∠IKC ≅ ∠JLD
m∠IKC = m∠JLD (SUBTRACTION PROPERTY OF CONGRUENCY)
So we have
m∠IKL + m∠JLD = 180°
∠IKL and ∠JLD are supplementary angles.
But ∠DLH and ∠JLD are supplementary angles.
∠IKL ≅ ∠DLH (CONGRUENT SUPPLEMENTS THEOREM)
Answer: 15
Explanation: quick maths in the brain
Answer:
decrease 3%
Step-by-step explanation:
sana makatulongggg
Let the 3 numbers be x,x+1,x+2
Given sum of those 3 consecutive integers are 78
X+x+1+x+2=78
3x+3=78
3(x+1)=78
X+1=26
X=26-1
X=25
Therefore the numbers are 25,26,27
