Answer:
it A or C depending on the site you use
Step-by-step explanation:
good luck
T________U________W
16
TU=UW
16=16
TW=TU+UW
TW=16+16
TW=32
F(x)=x
Domain: 1 2 3 4 5 6
Range: 1 2 3 4 5 6
F(x)=2x
Domain: 1 2 3 4
Range: 0 2 4 6
Answer:
The answer is 364. There are 364 ways of choosing a recorder, a facilitator and a questioner froma club containing 14 members.
This is a Combination problem.
Combination is a branch of mathematics that deals with the problem relating to the number of iterations which allows one to select a sample of elements which we can term "<em>r</em>" from a collection or a group of distinct objects which we can name "<em>n</em>". The rules here are that replacements are not allowed and sample elements may be chosen in any order.
Step-by-step explanation:
Step I
The formula is given as

n (objects) = 14
r (sample) = 3
Step 2 - Insert Figures
C (14, 3) =
= 
= 
= 
= 364
Step 3
The total number of ways a recorder, a facilitator and a questioner can be chosen in a club containing 14 members therefore is 364.
Cheers!
The answer would be .5 pounds
1 ounce is equal to .0625 lbs
so 8 * .0625 = .5
hope this helps :)
brainliest???