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Marrrta [24]
3 years ago
7

Use these numbers:

Mathematics
2 answers:
White raven [17]3 years ago
5 0

Answer:

45 and 5.

Step-by-step explanation:

aniked [119]3 years ago
5 0
The answer is 45 and 5
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21 is 30% of what number?
LiRa [457]
21 is 30% of 70 because .3*70=21
5 0
3 years ago
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Which of the following is true?
kow [346]

Answer:

C.

Step-by-step explanation:

A - Perpendicular lines always touch each other at least once.

B - Parallel lines never touch.

D- Not always true.

C is true. If they are not in the same plane they are skewed lines.

3 0
3 years ago
Graph the linear function whose equation is<br> y - 2 = - * (x + 1) by following these steps:
exis [7]

Answer:

The slope is -2/3

Step-by-step explanation:

With this its easier to get all of the x's on one side.

distribute the -2/3 to the x and 1. Also add a 2 on each side.

Thats leaves you with y=-2/3x+4/3

You than want to make a chart of x's and y's so you know what this graph looks like

x|y

-3|(10/3)

-2|(8/3)

-1|2

0|(4/3)

1|(2/3)

2|0

3|(-2/3)

To find the slope, it's (y2-y1)/(x2-x1)

So in this case, (0-2)/(2+1)

The slope is (-2/3)

4 0
3 years ago
Read 2 more answers
Slope and slope intercept form for 3y=12x+4
Neporo4naja [7]

Answer:Write in slope-intercept form, y=mx+b

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y=4x+43

hope this helps

4 0
2 years ago
Two chemical companies can supply a raw material. The concentration of a particular element in this material is important. The m
svp [43]

Answer:

As the calculated F lies in the acceptance region therefore we conclude that there is not sufficient evidence to support the claim that the variability in concentration may differ for the two companies. Hence Ha is rejected and H0 is accepted.

Step-by-step explanation:

As we suspect the variability of concentration F - test is applied.

n1=10    s1=4.7

n2=16      s2=5.8

And α = 0.05.

The null and alternate hypothesis are

H0: σ₁²=σ₂²       Ha:  σ₁²≠σ₂²

The null hypothesis is  the variability in concentration does not  differ for the two companies.

against the claim

the variability in concentration may differ for the two companies

The critical region F∝(υ1,υ2) = F(0.025)9,15= 3.12

and 1/F∝(υ1,υ2) = 1/3.77= 0.26533

where υ1= n1-1= 10-1= 9 and υ2= n2-1= 16-1= 15

Test Statistic

F = s₁²/s₂²

F= 4.7²/5.8²=0.6566

Conclusion :

As the calculated F lies in the acceptance region therefore we conclude that there is not sufficient evidence to support the claim that the variability in concentration may differ for the two companies. Hence Ha is rejected and H0 is accepted.

3 0
3 years ago
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