Answer:
0.58 = 58% probability she passes both courses
Step-by-step explanation:
We can solve this question treating the probabilities as a Venn set.
I am going to say that:
Event A: She passes the first course.
Event B: She passes the second course.
The probability she passes the first course is 0.67.
This means that 
The probability she passes the second course is 0.7.
This means that 
The probability she passes at least one of the courses is 0.79.
This means that 
a. What is the probability she passes both courses
This is 
.
We use the following relation:
So
0.58 = 58% probability she passes both courses
Answer:
4.83
Step-by-step explanation:
69$ is the sell price
7% is the commission rate
69$ x 7% = 4.83
Answer:
Therefore, The correct option is A. The probability of heads is 40%
Step-by-step explanation:
First set of trials : THTHTHTHHT ( T = Tails ; H = Heads)
Number of heads = 5
Number of outcomes = 10
Second set of trials : TTTHTTHTTH
Number of heads = 3
Number of outcomes = 10
Now, Total number of heads in the two tosses of the coin = 5 + 3 = 8
Total number of outcomes in the two tosses of the coin = 10 + 10 = 20
Therefore, The correct option is A. The probability of heads is 40%
If we let x be the first number and y be the second, we have (x + y) =13 and (2x - 3y) = 1.
From the first equation, we have x = (13- y). Substituting this into the second one, we have 2(13 - y) - 3y = 1.
Distributing the equation and re-arranging it, we now have (-5y) = (-26). Dividing both sides by -5, we have y = 5.
Now x = (13 - y) = 8.
Therefore, the two numbers are 5 and 8<span>. </span>
