C
a ratio of 5 : 5 simplifies to 1 : 1, which basically means we require the midpoint of the line segment
using the midpoint formula
M = [ (0 + 20 ), (15 + 0)] = (10, 7.5 )
Answer:
31.5cm²
Step-by-step explanation:
area of a triangle =1/2 b h
b= 7cm
h=9cm
1/2×7×9
= 1/2×63
= 31.5cm²
hypotenuse is unknown so,
c²=a²+b²
c²= 7² + 9²
= 49 + 81
c²= 130
c= 11.4cm
perimeter= 7 +9+11.4
=27.4cm
pls note that no unit was stated
What i did is that i did $1.50 time 8 = $12.00 and then do $30.00-12.00=$18.00
How To Find Inverses:
1. First, replace f(x) with y . ...
2. Replace every x with a y and replace every y with an x .
3. Solve the equation from Step 2 for y . ...
4. Replace y with f−1(x) f − 1 ( x ) . ...
5. Verify your work by checking that (f∘f−1)(x)=x ( f ∘ f − 1 ) ( x ) = x and (f−1∘f)(x)=x ( f − 1 ∘ f ) ( x ) = x are both true.
Answer:
Probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.
Step-by-step explanation:
We are given that a veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses with colic is 12 years. The average age of all horses seen at the veterinary clinic was determined to be 10 years. The researcher also determined that the standard deviation of all horses coming to the veterinary clinic is 8 years.
So, firstly according to Central limit theorem the z score probability distribution for sample means is given by;
Z = ~ N(0,1)
where, = average age of the random sample of horses with colic = 12 yrs
= average age of all horses seen at the veterinary clinic = 10 yrs
= standard deviation of all horses coming to the veterinary clinic = 8 yrs
n = sample of horses = 60
So, probability that a sample mean is 12 or larger for a sample from the horse population is given by = P( 12)
P( 12) = P( ) = P(Z 1.94) = 1 - P(Z < 1.94)
= 1 - 0.97381 = 0.0262
Therefore, probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.