Answer: 5 5/12 miles
Step-by-step explanation:
The following are the distance covered by Jada for the week.
Monday = 1 1/3 miles
Tuesday = 5/6 miles
Wednesday = 0
Thursday = 2 3/4 miles
Friday = 1 1/2 miles
Total distance for the week will be:
= 1 1/3 + 5/6 + 2 3/4 + 1 1/2
The lowest common multiple of 3,6,4 and 2 is 12. The fractions will then be
1 4/12 + 10/12 + 2 9/12 + 6/12
= 3 29/12
= 3 + 2 5/12
= 5 5/12
Jada ran 5 5/12 miles this week
When u got a + in the middle, parenthesis are not needed
3x^2 - 2 + 2x^2 - 6x + 3...now we combine like terms
5x^2 - 6x + 1 <==
Answer:
1. m ∠ 1 = 113°
2. m ∠ 2 = 67°
3. m ∠ 4 = 67°,
4. m ∠ 5 = 113°
5. m ∠ 6 = 67°
6. m ∠ 7 = 113°
7. m ∠ 8 = 67°
Step-by-step explanation:
Given AB║CD and m║n and m∠3=113°
Solution, since m and n are parallel lines so AB and CD are transversal lines.
So ∠2 and ∠3 makes a linear pair whose sum is equal to 180°.
(∠2 and ∠8),(∠3 and ∠7),(∠1 and ∠5),(∠4 and ∠6) are alternate interior angles.
(∠2 and ∠4),(∠1 and ∠3),(∠5 and ∠7),(∠6 and ∠8) are corresponding angles.
When two lines are parallel and their is a transversal line then the measure of alternate angles are equal and also the measure of corresponding angles are equal.
Hence the measure of all angles are:
1. m ∠ 1 = 113°
2. m ∠ 2 = 67°
3. m ∠ 4 = 67°,
4. m ∠ 5 = 113°
5. m ∠ 6 = 67°
6. m ∠ 7 = 113°
7. m ∠ 8 = 67°
Answer:
0.38% probability that the sample contains exactly two defective parts.
Step-by-step explanation:
For each part, there are only two possible outcomes. Either it is defective, or it is not. The probabilities for each part being defective are independent from each other. So we use the binomial probability distribution to solve this problem.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
In this problem we have that:
What is the probability that the sample contains exactly two defective parts?
This is
0.38% probability that the sample contains exactly two defective parts.
Answer:
Step-by-step explanation:
<h3>Trigonometry ratios:</h3>