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d1i1m1o1n [39]
3 years ago
11

*PLEASE HELP* I NEED TO FINISH THIS IN 30 MINUTES (I’ll give brainlist)

Mathematics
2 answers:
miskamm [114]3 years ago
5 0

Answer:

A

Step-by-step explanation:

garri49 [273]3 years ago
5 0

Answer:

C i think it's C but im not really sure

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Answer please.. Thank you in advance
sergeinik [125]
Picture is in correct
3 0
3 years ago
!PLEASE HELP WILL GIVE BRAINLIEST!
natita [175]

Answer:

34m = c

Step-by-step explanation:

For every month (m) you pay 34 dollars. However many months youu use that service time 34 equals your total cost (c).

4 0
3 years ago
Read 2 more answers
URGENT 25 POINTS MATH EQUATION PLEASE NO POINT STEAL!
Neko [114]

Answer:

it is diff because o the parentheses

Step-by-step explanation:

5 0
3 years ago
Complete. Express the product in simplest form.<br><br> 2/5 of 7/10 =
tester [92]
Of means multiply in math (most of the time). 
So multiply. 
2/5 x 7/10 = 14/50 divided by 2/2 = 7/25 
3 0
3 years ago
Read 2 more answers
Newton's law of cooling is:
Mnenie [13.5K]

Answer:

t = \frac{ln(\frac{21}{59})}{-0.15}=6.887 hr

So it would takes approximately 6.9 hours to reach 32 F.

Step-by-step explanation:

For this case we have the following differential equationÑ

\frac{du}{dt}= -k (u-T)

We can reorder the expression like this:

\frac{du}{u-T} = -k dt

We can use the substitution w = u-T and dw =du so then we have:

\frac{dw}{w} =-k dt

IF we integrate both sides we got:

ln |w| = -kt +C

If we apply exponential in both sides we got:

w = e^{-kt} *e^c

And if we replace w = u-T we got:

u(t)= T + C_1 e^{-kt}

We can also express the solution in the following terms:

u(t) = (T_i -T_{amb}) e^{kt} +T_{amb}

For this case we know that k =-0.15 hr since w ehave a cooloing, T_{i}= 70 F, T_{amb}=11F, we have this model:

u(t) = (70-11) e^{-0.15t} +11

And if we want that the temperature would be 32F we can solve for t like this:

32 = 59 e^{-0.15 t} +11

21=59 e^{-0.15 t}

\frac{21}{59} = e^{-0.15 t}

If we apply natural logs on both sides we got:

ln (\frac{21}{59}) =-0.15 t

t = \frac{ln(\frac{21}{59})}{-0.15}=6.887 hr

So it would takes approximately 6.9 hours to reach 32 F.

7 0
3 years ago
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