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3 years ago

What is 1*24 equals to

Mathematics

1 answer:

mezya [45]3 years ago

6 0

1*24= 24....

when any number is multiplied by one it gines the same no. for eg 241526×1=241526..

doesn't matter how greayer or smaller the number is....

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Four students decide to flip a coin a number of times and record their results. Dan flips his coin 5 times, Kelly flips her coin

Tcecarenko [31]

Answer:

Judah

Step-by-step explanation:

Because the more times you do the same thing over and over again then average it the more accurate it becomes

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jekas [21]

Answer: A (10)

Step-by-step explanation:

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3 years ago

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Consider the function f(x)equalscosine left parenthesis x squared right parenthesis. a. Differentiate the Taylor series about 0

dybincka [34]

I suppose you mean

$f(x)=\cos(x^2)$

Recall that

$\cos x=\displaystyle\sum_{n=0}^\infty(-1)^n\frac{x^{2n}}{(2n)!}$

which converges everywhere. Then by substitution,

$\cos(x^2)=\displaystyle\sum_{n=0}^\infty(-1)^n\frac{(x^2)^{2n}}{(2n)!}=\sum_{n=0}^\infty(-1)^n\frac{x^{4n}}{(2n)!}$

which also converges everywhere (and we can confirm this via the ratio test, for instance).

a. Differentiating the Taylor series gives

$f'(x)=\displaystyle4\sum_{n=1}^\infty(-1)^n\frac{nx^{4n-1}}{(2n)!}$

(starting at $n=1$ because the summand is 0 when $n=0$ )

b. Naturally, the differentiated series represents

$f'(x)=-2x\sin(x^2)$

To see this, recalling the series for $\sin x$ , we know

$\sin(x^2)=\displaystyle\sum_{n=0}^\infty(-1)^{n-1}\frac{x^{4n+2}}{(2n+1)!}$

Multiplying by $-2x$ gives

$-x\sin(x^2)=\displaystyle2x\sum_{n=0}^\infty(-1)^n\frac{x^{4n}}{(2n+1)!}$

and from here,

$-2x\sin(x^2)=\displaystyle 2x\sum_{n=0}^\infty(-1)^n\frac{2nx^{4n}}{(2n)(2n+1)!}$

$-2x\sin(x^2)=\displaystyle 4x\sum_{n=0}^\infty(-1)^n\frac{nx^{4n}}{(2n)!}=f'(x)$

c. This series also converges everywhere. By the ratio test, the series converges if

$\displaystyle\lim_{n\to\infty}\left|\frac{(-1)^{n+1}\frac{(n+1)x^{4(n+1)}}{(2(n+1))!}}{(-1)^n\frac{nx^{4n}}{(2n)!}}\right|=|x|\lim_{n\to\infty}\frac{\frac{n+1}{(2n+2)!}}{\frac n{(2n)!}}=|x|\lim_{n\to\infty}\frac{n+1}{n(2n+2)(2n+1)}$

The limit is 0, so any choice of $x$ satisfies the convergence condition.

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4 years ago

Half the quotient of 4 and a number y

shtirl [24]

Answer:

y = 1

Step-by-step explanation:

Hello!

2x2=4 so 2 is the quotient and half of 2 is obviously 1. So you add y to that and its y = 1.

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3 years ago

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Doss [256]

Answer:

B ignore bottom

Step-by-step explanation:

Your answer should be written in paragraph/essay format.

Any sources used should be cited at the bottom of your paper.

All answers should show you have learned something from Unit 9. Material from other units will not be graded for this assignment.

If you are stuck, you can think about the following topics: textile mills, interchangeable parts, the Lowell System, unions, labor reform, steamboats, railroads, coal, the telegraph, and/or new inventions.

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