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Usimov [2.4K]
3 years ago
13

In timara math class there are, 12 boys and 15 girls which of the following in the ratio to boys and girls in timaras math class

?
Mathematics
1 answer:
tiny-mole [99]3 years ago
7 0

Answer:

4:5

Step-by-step explanation:

If there are 12 boys and 15 girls, the ratio of boys to girls will be 12:15.

However, this can be simplified by dividing each number by 3. This can be done since both 12 and 15 are divisible by 3.

12:15

= 4:5

So, the ratio of boys to girls in Timara's class is 4:5

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Look ate the picture down below, and please help me i would really appreciate it
zavuch27 [327]

Answer:

  46°

Step-by-step explanation:

When secants intersect each other and a circle, the external angle (A) is half the difference of the intercepted arcs:

  ∠A = (arcDC -arcBC)/2

  12° = (arcDC -22°)/2 . . . . . . . fill in the given numbers

  24° = arcDC -22° . . . . . . . . . multiply by 2

  46° = arcDC . . . . . . . . . . . . . add 22°

5 0
3 years ago
What is the equation of the line that goes through (−1, −1) and is parallel to y = 6x − 1?
Alexandra [31]
Y-y1 = m(x-x1)
y-(-1) = 6 (x- -1)

answer: y = 6x-5
5 0
3 years ago
un rectangulo tiene 28 cm de perimetro y unos de sus lados mide 4 cm ¿cuantos cuadrados de 2 cm por lado se mecesitan para armar
seraphim [82]

Answer:

10 cuadrados

Step-by-step explanation:

Si uno de los lados de rectangulo es de 4cm entonces el lado parallelo tambien es de 4cm. Eso nos da 8cm del perimetro y nos quedan los otros dos lados que tienen la misma medida. Entonces dividimos el resto del perimetro por 2.

28 - 8 = 20cm

20cm / 2cm = 10cm

Ahora que tenemos todas las medidas podemos multiplicar el largo por el ancho para calcular el area del rectangulo

10cm * 4cm = 40cm^{2}

el cuadrado de 2cm tendra un area de

2cm * 2cm = 4cm^{2}

Ahora simplemente dividimos el area del rectangulo por el area del cuadrado para saber cuantos cuadrados necesitamos para armar ese rectangulo

40cm^{2} / 4cm^{2} = 10 cuadrados

3 0
2 years ago
If f(x) = 4(3x - 5), find f-1(x)
deff fn [24]

Answer:

f^{-1}(x) =  \frac{1}{12}(x+20)

Step-by-step explanation:

Given: f(x) = 4(3x - 5)

Is required to find f⁻¹(x)

f(x) = y = 4(3x - 5)

∴ y = 4 * 3x - 4 * 5

∴ y = 12x - 20 ⇒ add 20 to both sides

∴ y + 20 = 12x ⇒ divide both sides by 12

∴ \frac{1}{12} (y+20) = x

Replace the places of x and y.

∴ y=\frac{1}{12} (x+20)

∴ f^{-1}(x) =  \frac{1}{12}(x+20)

7 0
3 years ago
X + 3y &gt;/3<br> 5x + 3y -9
Radda [10]
5x +3y -9
Answer: 15y -9
8 0
2 years ago
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