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Olenka [21]
2 years ago
15

PLEASE HELP!!!!!!! I'LL MARK YOU AS BRAINLIEST AND GET 15 POINTS

Mathematics
1 answer:
morpeh [17]2 years ago
8 0

Answer:

The answer is probably C.

Step-by-step explanation:

So how the answer is C is,

It makes sense to divide x by 18 to get your answer. 2/5 is what you'll divided 18 by.

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Solve for k<br><br> 10/3 = k/9<br><br> K =
Gnesinka [82]
10/3=k/9
(10/3)9=k
30=k
5 0
2 years ago
Read 2 more answers
Pls help me it’s emergency plzz fast
earnstyle [38]

Answer:

67.3%

Step-by-step explanation:

Calculate profit = selling price - cost price

cost price = 50 × $28 = $1400

38 × $49 = $1862

12 × $40 = $480

selling price = $1862 + $480 = $2342

Profit = $2342 - $1400 = $942

% profit = \frac{profit}{cost} × 100%

             = \frac{942}{1400} × 100% ≈ 67.3% ( to 1 dec. place )

7 0
3 years ago
What are the roots of a poloynomail equation? x^2+24=11x
IrinaVladis [17]
X=8,3 . i have to type more to submit the answer
3 0
3 years ago
Read 2 more answers
How would I be able to get the step by step prosses of this and the answer of y?
Daniel [21]

Answer:

y = 3

Step-by-step explanation:

-7 = -4y + 5

Subtract 5 from both sides to isolate variable y:

-7 - 5 = -4y + 5 - 5

-12 = -4y + 0

-12 = -4y

Divide both sides by -4 to isolate variable y:

-12 ÷ -4 = -4y ÷ -4

(Negative ÷ Negative = Positive)

3 = 1y

3 = y

Check your work:

-7 = -4(3) + 5

Use PEMDAS:

-7 = -12 + 5

-7 = -7

Correct!

6 0
2 years ago
2sec^2x - secx - 1 = 0
Ivenika [448]
What are you trying to do here?
Solve the graph, or make it appear as something else?

First, we're going to take one sec (x) out so that we get:
sec (x) (2sec (x) -1 -1) = 0

sec (x) (2sec (x) -2) = 0


Then we're going to separate the two to find the zeros of each because anything time 0 is zero.

sec(x) = 0

2sec (x) - 2 = 0

Now, let's simplify the second one as the first one is already.

Add 2 to both sides:

2sec (x) = 2

Divide by 3 on both sides:

sec (x) = 1


I forgot my unit circle, so you'd have to do that by yourself. Hopefully, I helped a bit though!
8 0
3 years ago
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