Answer:
Did you mean How to edit text on word? There are 2 word, Microsoft Word Office and WordPad. The step I give you below is for both.
Explanation:
Steps to edit text on word
Step-1: Select the text you want to edit.
Step-2: Click on Home Tab.
Step-3: Select the style(s) you want to edit from the Font group
=(Happy)&(Birthday) this is how it would be formatted
Answer:
The answer is "Option A".
Explanation:
Add extra functionality, otherwise, it increases the R-square value, which is defined in the following points:
- To incorporate essential elements, R-square is explicitly promoted.
- It Increases the R-square value, which is an additional feature.
- It removes the features, which provide the value of the reduce R-square.
- After incorporating the additional features is used as the model, which is R-square, which is never reduced.
CORRECT QUESTION:
For the given program, how many print statements will execute?
public static void printShippingCharge(double weight) { if((weight > 0.0) && (weight <= 10.0)){ System.out.println(weight * 0.75); }
else if((weight > 10.0) && (weight <= 15.0)) { System.out.println(weight * 0.85); }
else if((weight > 15.0) && (weight <= 20.0)) { System.out.println(weight * 0.95); } }
public static void main(String args[]) {
printShippingCharge(18);
printShippingCharge(6);
printShippingCharge(25); }
Answer:
Two of the print statements will output values
Explanation:
These two calls to the printShippingCharge are the ones that will output values: printShippingCharge(18); and printShippingCharge(6);
The first if statement is true when the value of weight is 6 (weight > 0.0) && (weight <= 10.0)
The Third if statement is true when weight is 18 (weight > 15.0) && (weight <= 20.0)
NOTE: That I made correction to the variable weight. The question isn't consistent with the variable name. It used weight and itemWeight at different points this will lead to a compiller error
Answer:
132
Explanation:
We convert each number to base 10 (decimal) and multiply.
So 1011₂ = 1 × 2³ + 0 × 2² + 1 × 2¹ + 1 × 2⁰
= 1 × 8 + 0 × 4 + 1 × 2 + 1 × 1
= 8 + 0 + 2 + 1
= 11₁₀
1100₂ = 1 × 2³ + 1 × 2² + 0 × 2¹ + 0 × 2⁰
= 1 × 8 + 1 × 4 + 0 × 2 + 0 × 1
= 8 + 4 + 0 + 0
= 12₁₀
So, 1011₂ × 1100₂ = 11₁₀ × 12₁₀ = 132₁₀
So, the decimal equivalent of the product of 1011 and 1100 is 132
