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Arturiano [62]
3 years ago
5

Myra’s tutor used these steps to solve the problem 10x^2=90.

Mathematics
1 answer:
True [87]3 years ago
6 0

Answer:

Step-by-step explanation:

7x² = 1008

divide both sides by 7:

x² = 144

x = ±√144 = ±12

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In the equation x/35 = 7, what is the value of x? <br> A. 35 <br> B. 245 <br> C. 7 <br> D. 5
tensa zangetsu [6.8K]
The equation given in the question has one unknown variable in the ofrm of "x" and there is also a single equation. So it can be definitely pointed out that the exact value of the unknown variable "x" can be easily determined. Now let us focus on the equation given in the question.
x/35 = 7
x = 35 * 7
x = 245
So we can find from the above deduction that the value of the unknown variable "x" is 245. The correct option among all the options given in the question is option "B". I hope the procedure is not complicated for you to clearly understand.
8 0
3 years ago
Please help! 25 points
Zinaida [17]

Answer: Look at explanation

Step-by-step explanation:

32 = 2 x 2 x 2 x 2 x 2

27 = 3 x 3 x 3

16 = 2 x 2 x 2 x 2

No as 32 can be broken down to 8 and 4 and not just pime and not prime

7 0
2 years ago
The hours of daylight, y, in Utica in days x from January 1, 2013 can be modeled by the equation y = 2.89sin(0.0145x-1.40) + 10.
Pie

Answer:

9.3 hours

Step-by-step explanation:

Given

y = 2.89\sin(0.0145x-1.40) + 10.99.

Required

Hours of sunlight on Feb 21, 2013

First, calculate the number of days from Jan 1, 2013 to Feb 21, 2013

days = 52

So:

x = 52

So, we have:

y = 2.89\sin(0.0145x-1.40) + 10.99.

y = 2.89\sin(0.0145*52-1.40) + 10.99.

y = 2.89\sin(0.754-1.40) + 10.99.

y = 2.89\sin(-0.646) + 10.99.

y = 2.89*-0.6020 + 10.99.

y = -1.740 + 10.99.

y = 9.25

<em></em>y = 9.3<em> --- approximated</em>

8 0
3 years ago
When a plane flies into the wind, it can travel 3000 ml in 6 h . When it flies with the wind, it can travel the same distance in
jeka94

Answer:

  • plane: 550 mph
  • wind: 50 mph

Step-by-step explanation:

If p and w represent the speeds of the plane and wind, respectively, the speed into the wind is ...

  p - w = (3000 mi)/(6 h) = 500 mi/h

And, the speed with the wind is ...

  p + w = (3000 mi)/(5 h) = 600 mi/h

Adding these two equations gives us ...

  2p = 1100 mi/h

  p = 550 mi/h . . . . . . . divide by 2

Then the wind speed is ...

  w = 600 mi/h - p = (600 -550) mi/h

  w = 50 mi/h

The rate of the plane in still air is 550 mi/h; the rate of the wind is 50 mi/h.

4 0
3 years ago
Read 2 more answers
Please help I don't get this at all &gt;_&lt;
dangina [55]
Wow this... this is a lot YOU need help on
6 0
4 years ago
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