You plug in numbers -3 to 3 into the x variable of the equation and then plot those points
y = -2x
X = -3 y = (-2)(-3) = 6
X = -2 y = (-2)(-2) = 4
X = -1 y = (-2)(-1) = 2
X = 0 y = (-2)(0) = 0
X = 1 y = (-2)(1) = -2
X = 2 y =(-2)(2) = -4
X = 3 y = (-2)(3) = -6
In case that looks a little cluttered here are the points to graph:
(-3, 6) (-2, 4) (-1, 2) (0, 0) (1, -2) (2, -4) (3, -6)
Step-by-step explanation:
The error carolyn has made is that she hasn't subtracted properly.
2x + 3y - (2x +6y) = 2x - 2x + 3y - 6y = -3y.
Carolyn probably didn't use parentheses...
To do the thing in substitution, we single out x or y in any equation. In this case, i'm gonna single out the x in the 2nd eqn. In other words, i'll make x the subject of the 2nd eqn.
2x + 6y = 10
2x = 10 - 6y
x = 5 - 3y
Now we simply plug in 5 - 3y wherever x apperas in the 1st equation.
2 (5-3y) + 3y = 8
10 - 6y + 3y = 8
10 - 3y = 8
-3y = -2
y = 2/3
Then x = 5 - 3*2/3 = 3
x=3
y=2/3
Hope it helps:)
Answer:
Step-by-step explanation:
Given
+ 
← rationalise the denominator by multiplying by 
= + ( × )
= + 
=
Answer:
288 cm³
Step-by-step explanation:
cuboid formular: lengtg×width×height
I believe the answer would be 300. One eighth of the class would be 100 and 1/2 of the class would be 400. 800-(400+100)=300. Hope this helped!
