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frosja888 [35]
3 years ago
8

Solve for s. 3 = s - 2 s=

Mathematics
2 answers:
Alexxx [7]3 years ago
6 0

Answer:

3 = s - 2

s = 3 - 2

s = 1

what was hard lol

elena55 [62]3 years ago
3 0
The answer is 5 because 5-2=3. S=5
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Charlie has 2.86 beans.He needs to put 0.12 in each
MariettaO [177]

Answer:23.833...

Step-by-step explanation:

you would need to divide 2.86 and 0.12 but it goes on forever so you need to put ... after 333 or a line above 333 so your answer is 23.833...

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3 years ago
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Write the equation of a polynomial of degree 3, with zeros 1, 2 and -1 where f(0)=2
drek231 [11]

<u>Answer:</u>

The equation of a polynomial of degree 3, with zeros 1, 2 and -1 is x^{3}-2 x^{2}-x+2=0

<u>Solution:</u>

Given, the polynomial has degree 3 and roots as 1, 2, and -1. And f(0) = 2.

We have to find the equation of the above polynomial.

We know that, general equation of 3rd degree polynomial is  

F(x)=x^{3}-(a+b+c) x^{2}+(a b+b c+a c) x-a b c=0

where a, b, c are roots of the polynomial.

Here in our problem, a = 1, b = 2, c = -1.

Substitute the above values in f(x)

F(x)=x^{3}-(1+2+(-1)) x^{2}+(1 \times 2+2(-1)+1(-1)) x-1 \times 2 \times(-1)=0

\begin{array}{l}{\rightarrow x^{3}-(3-1) x^{2}+(2-2-1) x-(-2)=0} \\ {\rightarrow x^{3}-(2) x^{2}+(-1) x-(-2)=0} \\ {\rightarrow x^{3}-2 x^{2}-x+2=0}\end{array}

So, the equation is x^{3}-2 x^{2}-x+2=0

Let us put x = 0 in f(x) to check whether our answer is correct or not.

\mathrm{F}(0) \rightarrow 0^{3}-2(0)^{2}-0+2=2

Hence, the equation of the polynomial is x^{3}-2 x^{2}-x+2=0

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3 years ago
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10+q=10+q

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Anything helps please help me!
dimaraw [331]
5 1/2 = 11/2
11/2 x 3/4 = 33/8 = 4 1/8
answer is B. 4 1/8
8 0
3 years ago
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