Answer:
- secant slopes: -213.5, -187, -145, -113, -85
- tangent slope: -166
Step-by-step explanation:
A) the slope values you have put in your problem statement are correct. As you know, they are computed from ...
(change in gallons)/(change in time)
where the reference point for changes is P. Using the first listed point Q as an example, the secant slope is ...
(3410 -1275)/(5 -15) = 2135/-10 = -213.5 . . . . gallons per minute
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B) The average of the secant slopes for points Q adjacent to P is ...
(-187 +(-145))/2 = -332/2 = -166 . . . . gallons per minute
The tangent slope at point P is estimated at -166 gpm.
Answer: A, C, KA, CB
the letters represent the angles.
Answer: i am prety sure that it is 8 because when you see that there is a plus sign a minus sign and an equeal thats pretty much all you gotta do.
Step-by-step explanation:
To solve this, you have to figure out how they created the sequence, i.e., how did they get from 28 to 33 and then from 33 to 38 (etc.). If you subtract 28 from 33 the answer is 5, and the same is true for all the consecutive numbers in the sequence, so you have to add five to 43 to figure out the next term. You already have four terms, so we only need 4 more:
28, 33, 38, 43, 48, 53, 58, 63 63 is the 8th term.
