Answer:
Equations::
4c + 8t = 58
2c + 3t = 23
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Modify for elimination:
4c (4c*1) + 8t (8t*1)= 58
4c (2c*2) + 6t (3t*2)= 46
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Subtract and solve for "t":
2t (8t-6t) = 12
t = $6 (cost of one table)
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Solve for "c":
2c + 3t = 23
2c + 18 = 23
2c = 5
c = $2.50 (cost of one chair)
Answer:
He must use 3 GB or less
Step-by-step explanation:
Total cost = flat fee + number of GB * charge per GB
We know he must stay under 30 dollars so change the equals to less than or equal to (the opening facing the 30) and replace the total cost with 30
30≥ flat fee + number of GB * charge per GB
We know the flat fee is 21 and the charge per GB is 3
30≥ 21 + number of GB * 3
Subtract 21 from each side
30-21 ≥ 21-21 + number of GB * 3
9≥number of GB * 3
Divide by 3
9/3 ≥ number of GB * 3/3
3≥ number of GB
He must use 3 GB or less
1/18 would be your answer because 3 * 6 = 18. so 18 is your denominator. 1 * 1 is still 1 so that would be your numerator. You cant simplify the numerator because it's a one and can't be simplified by any other number but 18 can be simplified but it wouldn't make sense to just simplify the denominator and not the numerator so It would stay as 1/18.
The answer is 5/6
The only way to reduce fractions is if both numbers are even, and these are.
So divide 6 and 10 in half to reach 5/6
Because 5 is an odd number, you can't properly reduce anymore.