Given that <span>|x| + y ≥ 0, this means that y ≥ -|x|
Because |x| is always positive, then -|x| will always be negative.
The correct graph is the second graph.
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Are you sure you want ONLY the coefficient of b? If you expand this, you will have b in 3 of 4 terms.
According to Pascal's Triangle, the coefficients of (a+b)^4 are as follows:
1
1 2 1
1 3 3 1
1 4 6 4 1
So (a+b)^4 would be 1a^4 + 4a^3b + 6a^2b^2 + 4ab^3 + b^4
Here, you want (3 + b)^4. Here's what that looks like:
3^4 + 4[3^3*b] + 6[3^2*b^2] + 4[3*b^3] + 1[b^4]
Which coeff did you want?
43,44,45,45,46,47. Hope I helped
The coins differ in value by 5¢, so swapping the numbers of them will change the value by 5¢ for each unit difference in the numbers of coins. Since
40¢ = 8 * 5¢
there must be 8 more dimes than nickels.
There are (22 +8)/2 = 15 dimes and 7 nickels.
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You could write some equations for this problem. Let n, d represent numbers of nickels and dimes.
.. n +d = 22
.. 10d +5n - (10n +5d) = 40 . . . . . . . cents
.. 5(d -n) = 40 . . . . . . . . . . . . . . . . . . reversing the coin count changes the total by 5 cents for each unit of difference (d -n), as stated above.
.. d -n = 8 . . . . . . . . . . . . . . . . . . . . . . divide the preceding equation by 5
Adding this last equation to the first gives
.. 2d = 22 +8
.. d = 30/2 = 15
.. n = 22 -15 = 7
There are 15 dimes and 7 nickels.
