Answer with explanation:
For, a Matrix A , having eigenvector 'v' has eigenvalue =2
The order of matrix is not given.
It has one eigenvalue it means it is of order , 1×1.
→A=[a]
Determinant [a-k I]=0, where k is eigenvalue of the given matrix.
It is given that,
k=2
For, k=2, the matrix [a-2 I] will become singular,that is
→ Determinant |a-2 I|=0
→I=[1]
→a=2
Let , v be the corresponding eigenvector of the given eigenvalue.
→[a-I] v=0
→[2-1] v=[0]
→[v]=[0]
→v=0
Now, corresponding eigenvector(v), when eigenvalue is 2 =0
We have to find solution of the system
→Ax=v
→[2] x=0
→[2 x] =[0]
→x=0, is one solution of the system.
Hello the answer of above is given by me and this is my second I'd
I have found the answer of Q 4 and it's given in the attachment
<h3>Please mark above answer as brainliest </h3>
Answer:
( 7 , 4 )
given:
make y the subject in equation 2:
4x - y = 24
-y = 24 - 4x
y = 4x - 24
insert this in equation 1:
4x + 10y = 68
4x + 10(4x - 24) = 68
4x + 40x - 240 = 68
44x = 68 + 240
44x = 308
x = 7
solve for y:
y = 4x - 24
y = 4(7) - 24
y = 4
Answer:
Q + S = 360 - 55 - 45 = 260
Q = S
=> Q = 260/2 = 130
C is correct
