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2 years ago

13

Which system of equations does this graph represent?

1 answer:

jeyben [28]2 years ago

7 0

Answer:

1

Step-by-step explanation:

First, we can find the equation of the parabola. The standard form of a parabola is ax^2 + bx + c,

where c is the y-intercept. The y-intercept on the graph is -5, and every option starts with x^2, so the equation must be x^2 - 5. This rules out options 3 and 4.

Next, we can find the equation of the line. The options are all given in slope-intercept form: y = mx + b, where b is the y-intercept. The y-intercept on the graph is 1, and option 1 has 1 in the place of b. Therefore, option 1 is the answer.

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Trisha was making muffins from scratch. She scooped out 2 cups of all-purpose flour and estimated that it weighed 250 grams. Whe

Mice21 [21]

Answer:

first, she should have measured one cup of flower then estimated how much another one would weigh, and added the results together.

Step-by-step explanation:

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2 years ago

How would u find 20% of the regular price? what would you do with this amount to find the sale price

hjlf

Answer:

you would multiply the price by .20

Step-by-step explanation:

example:

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3 years ago

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kati45 [8]

Answer:

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Step-by-step explanation:

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8 0

3 years ago

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The 2 legs of a right triangle are 6' and 8' long what is the perimeter of the triangle

Vlad1618 [11]

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Step-by-step explanation:

8 0

2 years ago

A spherical balloon is being inflated at a rate of 3 cubic inches per second. Determine the change in the rate of the radius.How

Novay_Z [31]

Answer:

The rate rate of change of radius is $\frac{1}{48\pi}$ inches per second when the diameter is 12 inches.

The radius is changing more rapidly when the diameter is 12 inches.

Step-by-step explanation:

Consider the provided information.

A spherical balloon is being inflated at a rate of 3 cubic inches per second.

The volume of sphere is $V=\frac{4}{3}\pi r^3$

Differentiate the above formula with respect to time.

$\frac{dV}{dt}=4\pi r^2\frac{dr}{dt}$

Substitute the respective values in the above formula,

$3=4\pi 6^2\frac{dr}{dt}$

$\frac{1}{48\pi}=\frac{dr}{dt}$

The rate rate of change of radius is $\frac{1}{48\pi}$ inches per second when the diameter is 12 inches.

When d=16

$3=4\pi 8^2\frac{dr}{dt}$

$\frac{3}{256\pi}=\frac{dr}{dt}$

Thus, the radius is changing more rapidly when the diameter is 12 inches.

5 0

3 years ago