All categories

3 years ago

HELP HELP HELP HELP HELP HELL

Mathematics

1 answer:

vitfil [10]3 years ago

3 0

Answer:

it sould be D because rise over run.

Step-by-step explanation:

at the point its 5/6 and the only answer with that fraction is D. or it depends because if you're looking for the begening of the dotted lines then it's C .but if you're looking for end point then it's D. if you don't know ask me and ill see what i can do

You might be interested in

Find the probability of rolling a number less than 3 on a die. Pls help

lesantik [10]

Step-by-step explanation:

When a die is rolled, here it's Total possible outcome is= 6

and sample space is = 2 ( i.e. 1 & 2)

So. Probability of getting less than 3 = 26

=13

That's it

3 0

3 years ago

Read 2 more answers

I need to find the area. (please help me quick & the answer and explanation plz) POINTS: 15! please give real answers!!!!

Rufina [12.5K]

Area of triangle= 1/2 x Base x H

6 0

3 years ago

Read 2 more answers

The wheel in the adjacent figure has a radius of 61 feet. The clearance between the wheel and the ground is 11 feet. The rectang

Zanzabum

61 divide by 11 times 3

8 0

3 years ago

A water tank is in the shape of a cone.Its diameter is 50 meter and slant edge is also 50 meter.How much water it can store In i

Aneli [31]

To get the most accurate answer possible, we're going to have to go into some unsightly calculation, but bear with me here:

Assessing the situation:

Let's get a feel for the shape of the problem here: what step should we be aiming to get to by the end? We want to find out how long it will take, in minutes, for the tank to drain completely, given a drainage rate of 400 L/s. Let's name a few key variables we'll need to keep track of here:

$V$ - the storage volume of our tank (in liters)
$t$ - the amount of time it will take for the tank to drain (in minutes)

We're about ready to set up an expression using those variables, but first, we should address a subtlety: the question provides us with the drainage rate in liters per second. We want the answer expressed in liters per minute, so we'll have to make that conversion beforehand. Since one second is 1/60 of a minute, a drainage rate of 400 L/s becomes 400 · 60 = 24,000 L/min.

From here, we can set up our expression. We want to find out when the tank is completely drained - when the water volume is equal to 0. If we assume that it starts full with a water volume of $V$ L, and we know that 24,000 L is drained - or subtracted - from that volume every minute, we can model our problem with the equation

$V-24000t=0$

To isolate $t$ , we can take the following steps:

$V-24000t=0\\ V=24000t\\ \frac{V}{24000}=t$

So, all we need to do now to find $t$ is find $V$ . As it turns out, this is a pretty tall order. Let's begin:

Solving for $V$ :

About units: all of our measurements for the cone-shaped tank have been provided for us in meters, which means that our calculations will produce a value for the volume in cubic meters. This is a problem, since our drainage rate is given to us in liters per second. To account for this, we should find the conversion rate between cubic meters and liters so we can use it to convert at the end.

It turns out that 1 cubic meter is equal to 1000 liters, which means that we'll need to multiply our result by 1000 to switch them to the correct units.

Down to business: We begin with the formula for the area of a cone,

$V= \frac{1}{3}\pi r^2h$

which is to say, 1/3 multiplied by the area of the circular base and the height of the cone. We don't know $h$ yet, but we are given the diameter of the base: 50 m. To find the radius $r$ , we divide that diameter in half to obtain r = 50/2 = 25 m. All that's left now is to find the height.

To find that, we'll use another piece of information we've been given: a slant edge of 50 m. Together with the height and the radius of the cone, we have a right triangle, with the slant edge as the hypotenuse and the height and radius as legs. Since we've been given the slant edge (50 m) and the radius (25 m), we can use the Pythagorean Theorem to solve for the height $h$ :

$h^2+25^2=50^2\\ h^2+625=2500\\ h^2=1875\\ h=\sqrt{1875}=\sqrt{625\cdot3}=25\sqrt{3}$

With $h=25\sqrt{3}$ and $r=25$ , we're ready to solve for $V$ :

$V= \frac{1}{3} \pi(25)^2\cdot25\sqrt{3}\\ V= \frac{1}{3} \pi\cdot625\cdot25\sqrt{3}\\ V= \frac{1}{3} \pi\cdot15625\sqrt{3}\\\\ V= \frac{15625\sqrt{3}\pi}{3}$

This gives us our volume in cubic meters. To convert it to liters, we multiply this monstrosity by 1000 to obtain:

$\frac{15625\sqrt{3}\pi}{3}\cdot1000= \frac{15625000\sqrt{3}\pi}{3}$

We're almost there.

Bringing it home:

Remember that formula for $t$ we derived at the beginning? Let's revisit that. The number of minutes $t$ that it will take for this tank to drain completely is:

$t= \frac{V}{24000}$

We have our $V$ now, so let's do this:

$t= \frac{\frac{15625000\sqrt{3}\pi}{3}}{24000} \\ t= \frac{15625000\sqrt{3}\pi}{3}\cdot \frac{1}{24000} \\ t=\frac{15625000\sqrt{3}\pi}{3\cdot24000}\\ t=\frac{15625\sqrt{3}\pi}{3\cdot24}\\ t=\frac{15625\sqrt{3}\pi}{72}\\ t\approx1180.86$

So, it will take approximately 1180.86 minutes to completely drain the tank, which can hold approximately $V= \frac{15625000\sqrt{3}\pi}{3}\approx 28340615.06$ L of fluid.

5 0

3 years ago

Which statement about the following equation is true? 2x2-9x+2-1

Furkat [3]

Complete Question:

Which statement about the following equation is true?

$2x^2-9x+2 = -1$

A) The discriminant is less than 0, so there are two real roots

B) The discriminant is less than 0, so there are two complex roots

C) The discriminant is greater than 0, so there are two real roots

D) The discriminant is greater than 0, so there are two complex roots

Answer:

C) The discriminant is greater than 0, so there are two real roots

Step-by-step explanation:

The given equation is $2x^2-9x+2 = -1$ which by simplification becomes

$2x^2 - 9x + 3 = 0$

For a quadratic equation of the form $ax^2 + bx + c = 0$ , the discriminant is given by the equation, $D = b^2 - 4ac$

If the discriminant D is greater than 0, the roots are real and different

If the discriminant D is equal to 0, the roots are real and equal

If the discriminant D is less than 0, the roots are imaginary

For the quadratic equation under consideration, a = 2, b = -9, c = 3

Let us calculate the discriminant D

D = (-9)² - 4(2)(3)

D = 81 - 24

D = 57

Since the Discriminant D is greater than 0, the roots are real and different.

3 0

3 years ago