Ryan's data collection is true that Ryan did a survey he asked about qualitative data.
Given that Ryan called every school in the district to find out if they had a recycling program.
We know that there are two types of data:
Quantitative data deals with numbers and things that we can count or measure such as dimensions such as height, width, and length.
Qualitative data relating to characteristics and descriptions cannot be counted or measured, but are observable by their qualities such as smell, taste, and color.
If we ask for quantitative data, the survey will be quantitative. Data recycling means the quality of the data available.
They can ask for a yes or no answer, as in the Ryan investigation.
Hence, the correct statement about Ryan's data collection is: Ryan conducted a survey in which he asked about qualitative data.
Learn more about qualitative data from here brainly.com/question/27076284
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Answer:
explained
Step-by-step explanation:
a. daily requirement of milk = 4 liters
15 liters of milk is present
this 15 liters of milk will be used up in 
days
= 3(3/4) days , so after 3 days only more milk will be required to purchase.
b. daily milk consumption is reduced to half = 2 liters
Now, 15 liters of milk will be used up in 
= 7.5 or 7(1/2) days.
Hence now milk will be purchased after 7 days.
Answer:
90% confidence interval for the mean weight loss for the population represented by this sample assuming that the differences are coming from a normally distributed population is [1.989 ,13.5105]
Step-by-step explanation:
The data given is
Mean Std Dev
Before 177.25 29.325
After 169.50 22.431
Difference 7.75 8.598
Hence d`= 7.75 and sd= 8.598
The 90% confidence interval for the difference in means for the paired observation is given by
d` ± t∝/2(n-1) *sd/√n
Here t∝/2(n-1)=1.895 where n-1= 8-1= 7 d.f
and ∝/2= 0.1/2=0.05
Putting the values
d` ± t∝/2(n-1) *sd/√n
7.75 ±1.895 * 8.598 /√8
7.75 ± 5.7605
1.989 ,13.5105
90% confidence interval for the mean weight loss for the population represented by this sample assuming that the differences are coming from a normally distributed population is [1.989 ,13.5105]
Answer:
100000 = 8 (4) ^t
Step-by-step explanation:
We are multiplying by 4 each time
y = a (4)^t
The initial amount is 8
y = 8 (4)^t
We want to get to 100000
100000 = 8 (4) ^t
