The is Answer:
82
Explanation:
We observe that difference between first and second terms <span>=12−5=7</span>
Similarly difference between second and third terms <span>=19−12=7</span>
It shows that the given sequence of numbers is an arithmetic progression with common difference equal to 7.
We know that <span>nth</span> term of an AP whose first term is <span>a1</span> and whose common difference is d is given by
<span><span>an</span>=<span>a1</span>+<span>(n–1)</span>d</span>
To find the <span>12th</span> term, insert given values in the general expression
<span><span>a12</span>=5+<span>(12–1)</span>7</span>
<span><span>a12</span>=5+<span>(11)</span>7=5+77=<span>82</span></span>
Answer:
1) -5 and +5; 2) -9 and +9
Step-by-step explanation:
1) a² + 2ab + b² = 25
(a + b)² = 25 Wrote the left-hand side as a square
a + b = ±5 Took the square root of each side
All values of a + b are -5 and +5.
2) a² − 8ab + 16b² = 81
(a - 4b)² = 81 Wrote the left-hand side as a square
a - 4b = ±9 Took the square root of each side
All values of a - 4b are -9 and +9.
Answer: you have it right
Step-by-step explanation:
The answer is C ( or third one down ).
I got this answer by research, the credit goes to Mememebn and Zekke.
Hope this helps, if not, comment below please!!!
Answer:C
Step-by-step explanation:
