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Maurinko [17]
3 years ago
13

. If m angle TUV = (9x + 1)° , m angle TUW = (7x – 9)°, and m angle WUV = (5x - 11)°, find the value of x.​

Mathematics
1 answer:
Fed [463]3 years ago
4 0
Answer:

x = 7

Step-by-step explanation:

Suppose ray UW divides ∠TUV into two angles ∠ TUW and ∠ WUV.

Then, m∠TUV = m∠ TUW + m ∠ WUV

Given m∠TUV = (9x + 1), m∠ TUW = (7x - 9) and m ∠ WUV = (5x - 11)

Substitute these values in (i) we get

9x + 1 = 7x - 9 + 5x - 11
9x + 1 = 7x + 5x - 9 - 11
9x + 1 = 12x - 20
12x - 9x = 1 + 20
3x = 21
x = 21/3
x = 7

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On a typical long distance call you talk for 30 minutes. On a typical local call you talk for 10 minutes. Your phone company off
klio [65]

The number of long distance calls to be made can be obtained by linear programming

  • To minimize the phone bill, the number of long distance call to be made is none

Reason:

Maximum number of number of long distance calls = 15

Maximum number of local calls = 30

Number of minutes of calls to make each month = 240 minutes

Duration of each long distance call = 30 minutes

Duration of each local call = 10 minutes

Cost of long distance call = $0.08

Cost of local call = $0.03

Solution:

Let <em>X</em>, represent the number of long distance calls, and let <em>Y</em> represent the number local calls

The objective function is given as follows;

  • P = 0.08·(30)·X + 0.03·(10)·Y

P = 2.4·X + 0.3·Y

The constraints are;

X ≥ 0

Y ≥ 0

X ≤ 15

Y ≤ 30

30·X + 10·Y ≥ 240

Solving we have;

  • Y ≥ 24 - 3·X

The above inequality can be plotted with MS Excel

From the objective function, P = 2.4·X + 0.3·Y, the coefficient of the long

distance calls, <em>X</em> is larger than the coefficient of the local calls <em>Y</em>, therefore,

making the minimum possible number of long distance calls of 0, and 24

local calls will give a cost;

  • P = 2.4 × 0 + 0.3 × 24 = 7.2

Therefore, to minimize the phone bill, the number of long distance calls to

be made is <u>zero long distance calls</u>

Learn more about linear optimization here:

brainly.com/question/21491539

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3 years ago
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Three times each day, a quality engineer samples a component from a recently manufactured batch and tests it. Each part is class
Zielflug [23.3K]

Answer:

Step-by-step explanation:

Hello!

Three samples of components manufactured are taken per day. They are classified as:

D: "Conforming (suitable for its use)"

E: "Downgraded (unsuitable for the intended purpose but usable for another purpose)"

F: "Scrap (not usable)"

This classification includes the three events that may occur in your sample space S.

The experiment consists in recording the categories of the three parts tested in a day.

a. List the 27 outcomes in the sample space.

The possible outcomes in the space sample are the combinations of the three events. To avoid using the same letters as in the following questions I've named the evets as D, E, and F

S={DDD, DED, DFD, DEF, DFE, DEE, DFF, DDE, DDF , EDE, EEE, EFE, EED, EEF, EDF, EFD, EDD, EFF , FDF, FEF, FFF, FFE, FFD, FDE, FED, FDD, FEE}

b. Let A be the event that all the parts fall into the same category. List the outcomes in A.

  • A: "All the parts fall into the same category"

You have three possible outcomes for this event, that the three compounds are conforming, "DDD", that the three are unconforming, "EEE", or that the three compounds are scrap, "FFF". There are only three possible outcomes for this event.

S={DDD, EEE, FFF}

c. Let B be the event that there is one part in each category. List the outcomes in B.

  • B: "There is a part in each category"

This means, for example, The first one is conforming "D", the second one is unconforming "E" and the third one is scrap "F", then the first one may be unconforming "E", the second one is conforming "D" and the thirds one is scrap "F", and so on, you have 6 possible outcomes for this event:

S={DEF, DFE, EDF, EFD, FDE, FED}

d. Let C be the event that at least two parts are conforming. List the outcomes in C.

  • C: "At least two parts are conforming"

For this event, you can have two of the compounds to be considered conforming or the three of them.

S={DDD, DED, DFD, DDE, DDF , EDD, FDD}

A total of 7 combinations fit this event.

e. List the outcomes in A ∩ C

A ∩ C is an intersection between the event A and C, this means that there must be outcomes that are shared by both events.

Possible outcomes for A: S={DDD, EEE, FFF}

Possible outcomes for C: S={DDD, DED, DFD, DDE, DDF , EDD, FDD}

As you can see there is only one possible outcome shared by these two events. So the possible outcomes for A ∩ C are:

S= {DDD}

f. List the outcomes in A U B

A U B is the union between these two events, to see what outcomes this union has you have to add every outcome of A plus every outcome of B minus the possible outcomes that A and B share:

Possible outcomes for A: S={DDD, EEE, FFF}

Possible outcomes of B: S={DEF, DFE, EDF, EFD, FDE, FED}

The possible outcomes for A U B are:

S={DDD, EEE, FFF, DEF, DFE, EDF, EFD, FDE, FED, EEF, EDF, EFD, }

g. List the outcomes in A ∩ c

c is the complementary event of C, it could also be symbolized as C^c

If C: "At least two parts are conforming" then its complemental event will be

  • C^c: At most one part is conforming"

This means that one or none parts are conforming, and it's possible outcomes are:

S= {DEF, DFE, DEE, DFF, EDE, EEE, EFE, EED, EFF , FDF, FEF, FFF, FFE, FFD, FDE, FED, FEE}

Possible outcomes for A: S={DDD, EEE, FFF}

As you see there are two events on "A" that also appear in the definition of "C^c"

The possible outcomes for A ∩ C^c are:

S= {EEE, FFF}

h. List the outcomes in Ac ∩ C

Ac is the complementary event of A, also symbolized as A^c

If A: "All the parts fall into the same category", then its complemental event will be

  • A^c: "Not all the parts fall into the same category"

and its possible outcomes are the remaining 24 occurrences:

S={DED, DFD, DEF, DFE, DEE, DFF, DDE, DDF , EDE, EFE, EED, EEF, EDF, EFD, EDD, EFF , FDF, FEF, FFE, FFD, FDE, FED, FDD, FEE}

Possible outcomes for C: S={DDD, DED, DFD, DDE, DDF , EDD, FDD}

As you can see the events A^c and C share 6 occurrences in common, so the possible outcomes for the intersection will be:

S= {DED, DFD, DDE, DDF , EDD, FDD}

i. Are events A and C mutually exclusive? Explain.

Two events are mutually exclusive when the occurrence of one of them keeps the other from occurring, i.e. it can happen one or the other but not both.

A and C are not mutually exclusive since the three pieces may have the same category, "D: conforming" and at least two of them to be conforming "DD-" at the same time in the occurrence "DDD" and mutually exclusive events never happen at the same time.

ii. Are events B and C mutually exclusive? Explain.

B and C are mutually exclusive, you can easily see this if you compare the possible outcomes of both events:

Possible outcomes of B: S={DEF, DFE, EDF, EFD, FDE, FED}

Possible outcomes for C: S={DDD, DED, DFD, DDE, DDF , EDD, FDD}

There are no shared elements by these events. This means that if you were to take three pieces randomly sampled in one day and fit the definition of B, then they will not fir the definition of C and vice versa.

I hope it helps!

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drek231 [11]

Answer:

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Step-by-step explanation:

Given,

x is the number of math problem Lucy solved.

y is the number of  pages she read.

She can do each math problem in  5 minutes, therefore she can solve x number of questions into 5 \times x=5x minutes.

She can read each page in 2.5 minutes, therefore she can read y pages in 2.5y minutes.

As per given detail,

5x+2.5y=105 equation 1.

And,

It is given that number of math problems Lucy solved is 3 times the number of pages she read.

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We need to find x and y intercept of each of the equation to graph them.

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Join these two points.

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Step-by-step explanation:

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