Answer:
Explanation:
You need to find the probability that exactly three of the first 11 inspected packages are damaged and the fourth is damaged too.
<u>1. Start with the first 11 inspected packages:</u>
a) The number of combinations in which 11 packages can be taken from the 20 available packages is given by the combinatory formula:
b) The number of combinations in which 3 damaged packages can be chossen from 7 damaged packages is:
c) The number of cominations in which 8 good packages can be choosen from 13 good pacakes is:
d) The number of cominations in which 3 damaged packages and 8 good packages are chosen in the first 11 selections is:
e) The probability is the number of favorable outcomes divided by the number of possible outcomes, then that is:
Subsituting:
<u>2. The 12th package</u>
The probability 12th package is damaged too is 7 - 3 = 4, out of 20 - 11 = 9:
<u>3. Finally</u>
The probability that exactly 12 packages are inspected to find exactly 4 damaged packages is the product of the two calculated probabilities:
Answer: I'm pretty sure its 483c try it
Step-by-step explanation:
Answer:
$25
Step-by-step explanation:
c=30−(0.25)(20)
c=30+(−5)
c=(30+(−5)
30-5
Combine Like Terms
c=25
X x_ = (13+14+11+11+13+10)/6=12 x-x_ (x-x_)^2 standard deviation is
13 for all X_ it is the same 13-12=1 . 1. =(12/6)^1/2=1.41421
14 14-12=2 . 4.
11 11-12=-1 . 1.
11 11-12 =-1 . 1.
13 13-12=1 . 1.
10 10-12=-2. 4.
The coefficient of a is 7