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Alex787 [66]
3 years ago
12

PLEASE HELP PLS PLS WITH MY MATH

Mathematics
2 answers:
dmitriy555 [2]3 years ago
8 0

Answer:

answer to the question is A

katen-ka-za [31]3 years ago
5 0
Actually The answer is 0 or none. I don’t know if the question was a joke considering that it doesn’t say brown on the chart but the answer is 0 or none
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HELPP!!!!! ASAPPP!!!!!!
Verdich [7]

Answer:

4n plus 16

Step-by-step explanation:

3 0
3 years ago
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En un triángulo isósceles, el lado desigual mide 8 cm menos que cada uno de los lados iguales. Calcula los lados del triángulo s
kupik [55]

The given problem is "In an isosceles triangle, the uneven side is 8 cm shorter than each of the equal sides. Calculate the sides of the triangle knowing that the perimeter is 31 cm.

To find,

The sides of the triangle.

Solution,

Let each of equal sides are x.

The unequal sides is x-8.

Perimeter is the sum of all the sides. So,

31 = x+x+x-8

31+8=3x

3x = 39

x = 13

So, the equal sides are 13 cm.

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7 0
3 years ago
An English class has read the first 384 pages of their novel.
Pavel [41]
X - the total number of pages

75\%x=384 \\
\frac{75}{100}x=384 \\
\frac{3}{4}x=384 \\
x=384 \times \frac{4}{3} \\
x=128 \times 4 \\
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There are 512 pages in the novel.
6 0
3 years ago
Which expression is equivalent to 14(2−5x+6) ?
goblinko [34]

Answer:

c

Step-by-step explanation:

6 0
3 years ago
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F(x)=1/2×+6 plz helpppppppppp​
FromTheMoon [43]

Answer:

The solution set can be given as:

\{x|x\ \epsilon\ R,x\neq -3\}

Step-by-step explanation:

Given function:

f(x)=\frac{1}{2x+6}

To find the domain of the function in set notation.

Solution:

For the function f(x) to exist the denominator must be ≠ 0

We have the denominator (2x+6) which  cannot be = 0.

Thus, we can find the domain of the function using the above relation.

The function f(x) will not exist when:

2x+6=0

Solving for x

Subtracting both sides by 6.

2x+6-6=0-6

2x=-6

Dividing both sides by 2.

\frac{2x}{2}=\frac{-6}{2}

∴ x=-3

Thus, the function will not exist at x=-3. This means it has all real number solutions except -3.

The solution set can be given as:

\{x|x\ \epsilon\ R,x\neq -3\}

3 0
4 years ago
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