P^ = 9/300 = 0.03
H0 = p < 5%
H1 = p > 5%
standard deviation of sample distribution = sqrt[p(1 - p) / n] = sqrt[0.05(1 - 0.05)/300] = sqrt(0.0001583) = 0.01258
test statistics, z = (p^ - p) / standard deviation = (0.03 - 0.05) / 0.01258 = -1.589
P(-1.589) = 1 - P(1.589) = 1 - 0.94402 = 0.05598
Since, p = 0.05598 < significant level of 0.1, we reject the H0.
i.e. There is no sufficient evidence to suggest that the proportion of defective batteries is less than 5%.
The p-value of the test is 0.05598
Answer:
290.25 dollars earned
Step-by-step explanation:
32.25 times 9
Answer:
im thinking n is 6.5 not sure wait not 6.5 its 3.5
Answer:
-2
Step-by-step explanation:
15x+6=6x-12
15x-6x=-12-6
9x=-18
x=-2
Answer:
x≥ -7 x -y/3
Step-by-step explanation:
