Please help due tonight !!!!

Jose is working two summer jobs, making $10 per hour washing cars and $9 per hour walking dogs. Last week Jose worked a total of

Setler [38]

Answer:

x+y =13

10x + 9y =122

Step-by-step explanation:

Hi, to answer this question we have to write a system of equations:

The sum of the hours he worked washing cars (x) and the hours he worked walking dogs(y) will be equal to the total hours worked (13)

x+y =13

For the second equation the product of the number of hours he worked washing cars(x) and the price per hour ($10) plus the product of the number of hours he worked walking dogs (y) and the price per hour ($9) will be equal to the total amount earned (122)-

10x + 9y =122

So, the system of equations is:

x+y =13
10x + 9y =122

Where:

x: number of hours Jose worked washing cars

y: number of hours Jose worked walking dogs

7 0

3 years ago

Read 2 more answers

Wire of length 20m is divided into two pieces and the pieces are bent into a square and a circle. How should this be done in ord

blondinia [14]

Answer:

The radius of the circle ,r= 1.43 m

The length of the side of square ,a= 2.77 m

Step-by-step explanation:

Given that

L= 20 m

Lets take radius of the circle =r m

The total parameter of the circle = 2π r

Area of circle ,A=π r²

The side of the square = a m

The total parameter of the square = 4 a

Area of square ,A'=a²

The total length ,L= 2π r+ 4 a

20 = 2π r+ 4 a

r=3.18 - 0.63 a

The total area = A+ A'

A" =π r² +a²

A"= 3.14(3.18 - 0.63 a)² + a²

For minimize the area

$\dfrac{dA"}{da}=0$

3.14 x 2(3.18 - 0.63 a) (-0.63) + 2 a = 0

3.14 x (3.18 - 0.63 a) (-0.63) + a = 0

-6.21 + 1.24 a + a=0

2.24 a = 6.21

a=2.77 m

r= 3.18 - 0.63 a

r= 3.18 - 0.63 x 2.77

r=1.43 m

Therefore the radius of the circle ,r= 1.43 m

The length of the side of square ,a= 2.77 m

4 0

3 years ago

Read 2 more answers

The number a point corresponds to on a number line is called it's

cestrela7 [59]

It's called a coordinate

8 0

3 years ago

I need help fast please!!

kaheart [24]

Solution set is: ( $7,\frac{13}{3}$ )

Option B is correct

Step-by-step explanation:

We need to find the solution to system of equations

$y=\frac{1}{3}x+2\\y=\frac{4}{3}x-5$

Let:

$y=\frac{1}{3}x+2\,\,\,eq(1)\\y=\frac{4}{3}x-5\,\,\,eq(2)$

Putting value of y from eq(2) into eq(1)

$\frac{4}{3}x-5=\frac{1}{3}x+2\\Combining\,\,like\,\,terms:\\\frac{4}{3}x-\frac{1}{3}x=2+5\\Taking\,\,LCM\\\frac{4x-1x}{3}=7\\\frac{3x}{3}=7\\x=7$

So, value of x=7

Putting value of x into equation 1 to find the value of y:

$y=\frac{1}{3}x+2\\y=\frac{1}{3}(7)+2\\y=\frac{7}{3}+2\\Taking\,\,LCM\\y=\frac{7+2*3}{3}\\y=\frac{7+6}{3}\\y=\frac{13}{3}$

So, value of y = $\frac{13}{3}$

Solution set is: ( $7,\frac{13}{3}$ )

Option B is correct

Keywords: System of equations

Learn more about system of equations at:

#learnwithBrainly

3 0

4 years ago

The time for this event for boys in secondary school is known to possess a normal distribution with a mean of 460 seconds and a

AlekseyPX

Answer:

The time that the boys need to beat in order to earn a certificate of recognition from the fitness association is 511.264 seconds.

Step-by-step explanation:

We are given that the time for this event for boys in secondary school is known to possess a normal distribution with a mean of 460 seconds and a standard deviation of 40 seconds.

The fitness association wants to recognize the fastest 10% of the boys with certificates of recognition.

Let X = time for this event for boys in secondary school

SO, X ~ Normal( $\mu=460,\sigma^{2} =40^{2}$ )

The z-score probability distribution for normal distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = mean time = 460 seconds

$\sigma$ = standard deviation = 40 seconds

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, it is given that the fitness association wants to recognize the fastest 10% of the boys with certificates of recognition, which means;

P(X > x) = 0.10 {where x is the required time which boy need to beat}

P( $\frac{X-\mu}{\sigma}$ > $\frac{x-460}{40}$ ) = 0.10