<h2>
The first term of the given sequence (a) = 6561</h2>
Step-by-step explanation:
Let the first term = a and common difference = d
Given,
= 729 and 
= 243
To find, the first term of the given sequence (a) = ?
We know that,
The nth term of a G.P.
The 3rd term of a G.P.
⇒ 
= 729 ..............(1)
The 4th term of a G.P.
⇒ 
= 243 ..............(2)
Dividing equation (2) by (1), we get
= 
⇒ 
Put in equation (1), we get
= 729
⇒ 
= 729
⇒ a = 9 × 729 = 6561
∴ The first term of the given sequence (a) = 6561
D pass through. The taxes “pass through” to the owners
Subtracting the polynomials will give us:
(7.8x-3.4y+z)-(-9.2x+4.8y-2.1z)
=(7.8x+9.2x)+(-3.4y-4.8y)+(z+2.1z)
=17x-8.2y+3.1z
Answer: 17x-8.2y+3.1z
Answer:
Step-by-step explanation:
See the attached figure.
y₁ = 25x and y₂ =x²
The intersection between y₁ and y₂
25x = x²
x² - 25x = 0
x(x-25) = 0
x = 0 or x =25
y = 0 or y =25² = 625
The points of intersection (0,0) and (25,625)
To find the volume of the solid obtained by rotating about the y-axis the region bounded by y₁ and y₂
y₁ = 25x ⇒ x₁ = y/25 ⇒ x₁² = y²/625
y₂ =x² ⇒ x₂ = √y ⇒ x₂² = y
v = ∫A(y) dy = π ∫ (x₂² - x₁²) dy
∴ V =
F(1) = 3
f(2) = 3 + 5 = 8
f(3) = 8 + 5 = 13
f(n) = 5(n - 1) + 3
f(n) = 5n - 2
