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belka [17]
3 years ago
6

Need help with this please

Mathematics
1 answer:
Studentka2010 [4]3 years ago
7 0

Answer:

.

Step-by-step explanation:

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James was saving his money to buy a new bicycle. The bicycle originally costs $150 but then the store owner marked up its price
Volgvan

Answer:

$180

Step-by-step explanation:

To find the new cost, multiply the original cost by 1.2

150(1.2)

= 180

So, the new cost of the bicycle is $180

5 0
3 years ago
Read 2 more answers
If one of the roots of the equation x²- 4x + k=0exceeds the other by 2, then find the roots and determine the value of k
BaLLatris [955]

Answer:

roots: 1 and 3

k = 3

Step-by-step explanation:

2 roots: p and p+2

(x-p) (x-p-2) = x² - 4x + k

x² -2px -2x + p² + 2p = x² - 2 (p+1)x + (p² + 2p) = x² -4x + k

-2 (p+1) = -4

p+1 = 2

p = 1   ... root 1

p' = 1+2 = 3   ... root 2

k = p² + 2p = 3

check: (x-1) (x-3) = x² - 4x + 3 = x² - 4x + k

6 0
3 years ago
271403 rounded to the nearest ten thousand
ella [17]

Answer:

271,403 is rounded to 270,000 because the 1403 before it is less than 5000, 4 and below drop it down, 5 or more bump it up.

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
HELP PLEASE!!!!!!!!!!!!
Bogdan [553]

Answer:

See the explanation.

Step-by-step explanation:

We are given the function f(x) = x² + 2x - 5

Zeros :

If f(x) = 0 i.e. x² + 2x - 5 = 0

The left hand side can not be factorized. Hence, use Sridhar Acharya formula and  

x= \frac{-2+\sqrt{2^{2}-4\times(-5)\times1 } }{2} and  

x= \frac{-2-\sqrt{2^{2}-4\times(-5)\times1 } }{2}

⇒ x = -3.45 and 1.45

Y- intercept :

Putting x = 0, we get, f(x) = - 5, Hence, y-intercept is -5.

Maximum point :

Not defined

Minimum point:  

The equation can be expressed as (x + 1)² = (y + 5)

This is an equation of parabola having the vertex at (-1,-5) and axis parallel to + y-axis

Therefore, the minimum point is (-1,-5)

Domain :  

x can be any real number

Range:  

f(x) ≥ - 6

Interval of increase:

Since this is a parabola having the vertex at (-1,-5) and axis parallel to + y-axis.

Therefore, interval of increase is +∞ > x > -1

Interval of decrease:

-∞ < x < -1

End behavior :  

f(x) = x^{2} +2x-5 =x^{2}  (1+\frac{2}{x} -\frac{5}{x^{2} } )

So, as x tends to +∞ , then f(x) tends to +∞

And as x tends to -∞, then f(x) tends to +∞. (Answer)

7 0
3 years ago
What is the solution of the inequality 2x - 9&lt;7?
notka56 [123]
I think it is d I think not sure tho
5 0
3 years ago
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