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nikklg [1K]
3 years ago
13

What is the slope of the line through (-7,-2) and (−6,7)?

Mathematics
1 answer:
Murrr4er [49]3 years ago
4 0

Answer:

slope = 9  

Step-by-step explanation:

To find the slope of a line that passes through a pair of points, use the slope formula, m = \frac{y_2-y_1}{x_2-x_1}. Substitute the x and y values of (-7,-2) and (-6,7) into the formula and simplify:

m = \frac{(7)-(-2)}{(-6)-(-7)} \\m = \frac{7+2}{-6+7} \\m = \frac{9}{1} \\m = 9

So, the slope is 9.

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Solve for m and q:<br> m+ 2 = q - 4<br> 5m - 33 = q+1
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8 0
4 years ago
What is the difference? StartFraction x Over x squared minus 16 EndFraction minus StartFraction 3 Over x minus 4 EndFraction Sta
katovenus [111]

Answer:

The option "StartFraction negative 2 (x + 6) Over (x + 4) (x minus 4) EndFraction" is correct

That is \frac{-2(x+6)}{(x+4)(x-4)}

Therefore \frac{x}{x^2-16}-\frac{3}{x-4}=\frac{-2(x+6)}{(x+4)(x-4)}

Step-by-step explanation:

Given problem is StartFraction x Over x squared minus 16 EndFraction minus StartFraction 3 Over x minus 4 EndFraction

It can be written as below :

\frac{x}{x^2-16}-\frac{3}{x-4}

To solve the given expression

\frac{x}{x^2-16}-\frac{3}{x-4}

=\frac{x}{x^2-4^2}-\frac{3}{x-4}

=\frac{x}{(x+4)(x-4)}-\frac{3}{x-4}  ( using the property a^2-b^2=(a+b)(a-b) )

=\frac{x-3(x+4)}{(x+4)(x-4)}

=\frac{x-3x-12}{(x+4)(x-4)} ( by using distributive property )

=\frac{-2x-12}{(x+4)(x-4)}

=\frac{-2(x+6)}{(x+4)(x-4)}

\frac{x}{x^2-16}-\frac{3}{x-4}=\frac{-2(x+6)}{(x+4)(x-4)}

Therefore \frac{x}{x^2-16}-\frac{3}{x-4}=\frac{-2(x+6)}{(x+4)(x-4)}

Therefore the option "StartFraction negative 2 (x + 6) Over (x + 4) (x minus 4) EndFraction" is correct

That is \frac{-2(x+6)}{(x+4)(x-4)}

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4 years ago
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