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ankoles [38]
3 years ago
8

Evaluate "50 decreased by a number" if the number = 30

Mathematics
1 answer:
a_sh-v [17]3 years ago
6 0

Answer:

Step-by-step explanation:

20

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Out of 1,100 discs tested, 13 are defective. Estimate the number of defective discs in a batch of 41,000.
Luba_88 [7]
13/1,100 = x/ 41,000 (in English, this reads 13 out of 1,100 equals x out of 41,000) * by 41,000 and you get 41,000 x 13/1,100 = x
which is about 485

8 0
3 years ago
Which of the following are rational numbers? Check all that are true.
chubhunter [2.5K]

Answer:

no so e are not and some are

3 0
3 years ago
Which number is a zero of the function f?<br> f(x) = x2 - x - 6<br> F 6<br> G2<br> H 3<br> IO
Serhud [2]

Answer:

zeros of the function are −2 and 3

Step-by-step explanation:

there is no -2 so H.3

8 0
3 years ago
Read 2 more answers
A cylindrical container of three rubber balls has a height of 18 centimeters and a diameter of 6 centimeters. each ball in the c
photoshop1234 [79]
You have 3 spheres inside a cylinder like for a can of tennis balls. Notice the radius of the cylinder is 3 cm, the same as the radius of the spheres, so the spheres just fit width wise, and 3 spheres height would be 6 radius lengths or 18, which is the same as the cylinder height, so the three spheres are packed to the best fit.

The volume not occupied by the spheres will be the total cylinder volume take away the three spheres volumes.

The cyinder volume with height h=18 and radius r=3 will be approx..
V cyl= \pi r^2h =  \pi *3^2*18 = 508.7 ~cm^3

The volume of 3 spheres with radius r=3 will be
3*V sph=3*  \frac{4}{3}  \pi r^3=3* \frac{4}{3}  \pi *3^3=339.12~cm^3

The volume unoccupied by the spheres inside the cylinder is the difference in those two volumes..
508.68 - 339.12 = 169.56  or 170 cubic centimeters

7 0
3 years ago
Of three dice, two are labeled normally: 1, 2, 3, 4, 5 , and 6. The third die has sides labeled 2,4,6,8,10, and 12. Two dice are
jolli1 [7]

The ratio of the frequency of a prime rolled using the first two (ordinary)dice to the frequency of a prime rolled using the unusual die and one ordinary die is

  • \frac{15}{13}

<h3>The Cases and there Probable Results</h3>

There are a total of 36 equally probable ways the dice can fall

In the first case, primes are achieved for the following results:

  • 2 (one way possible),
  • 3 (two ways possible),
  • 5 (4 ways possible),
  • 7 (six ways possible), and
  • 11 (2 ways possible.

So primes are achieved in a total of 15 ways.

In the second case, the prime possibilities are

  • 3 (one way possible),
  • 5 (two ways),
  • 7 (3 ways),
  • 11 (3 ways),
  • 13 (3 ways), and
  • 17 (just one way).

The total is 13 ways.

<h3>How to calculate the ratio of the frequency</h3>

Therefore

How to calculate the ratio of the frequency is Mathematically given as

Frequency ratio is \frac{15}{13}

For more information on dice,

visithttps://brainly.com/question/2264527

7 0
2 years ago
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