Here you have two terms connected by the "subtraction" symbol.
The two coefficients are 2 and 32, and one factor common to both of these is 2. Thus, <span>2x^2-32y^2 = 2(x^2-16y^2).
You could stop here. But it'd make more sense to continue, since x^2-16y^2 is easy to factor:
The three factors of </span><span>2x^2-32y^2 are 2, x-4 and x+4</span>
Ok so given the point (r, theta)
The corresponding Cartesian point is (r*sin(theta), r* cos(theta)) you can think about this by analyzing the points on a unit circle which is a graph of a polar circle with radius 1 and angle theta
Answer:
Explanation:
3 + 2x - y = 0
Or 2x - y = -3 (1)
-3-7y = 10x
Or -10x - 7y = 3 (2)
2x - y = -3 (1)
-10x - 7y = 3 (2)
———————
Multiply 5 to (1)
5(2x - y = -3)
-10x - 7y = 3
———————
10x - 5y = -15
-10x - 7y = 3
———————
-12y = -12
y = -12/-12
y = 1
Plug y value in (1)
2x - 1 = -3
2x = -3 + 1
2x = -2
x = -2/2 = -1
Therefore, x = -1 and y = 1
