Answer:
what do you mean ???????????
PART A:
x | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 |
y | 6 | 5.5 | 5 | 4.5 | 4 | 3.5 | 3 | 2.5 | 2 | 1.5 | 1 | 0.5 | 0 |
x=hours
y=candle length
PART B:
Yes it is a function because you can input the values
PART C:
Yes, it will still be a function but with a different different y value
The easiest way to solve this problem is to find the equation of the line joining these two points, then get the values of the points on this line.
We have first point (x1,y1) = (-3,4) and second point (x2,y2) = (1,1).
The equation of the line is y = mx + c
The slope (m) = (y2-y1) / (x2-x1) = (1-4) / (1--3) = -0.75
Then we will use one of these points to get the value of c as follows:
y = mx + c
1 = -0.75 (1) + c ..............> c = 1.75
The equation of this straight line is:
y = -0.75 x + 1.75
Now to get points on this line, we will assume values for either x or y and calculate the other as follows:
1- For x = 0:
y = -0.75 (0) + 1.75 = 1.75
point is (0,1.75)
2- For y = 0:
0 = -0.75 x + 1.75 ..............> x = 2.334
point is (2.334,0)
3- For x = 2:
y = -0.75(2) + 1.75 = 0.25
point is (2,0.25)
Answer:
c=81
Step-by-step explanation:
Take half of b: 18/2=9
Square the result: 9²=81
This is your value of c that will result in a perfect square trinomial, which is c=81. If you were to keep going, you would do the following:
x²+18x+81=25+81
x²+18x+81=106
(x+9)^2=106 <-- Final simplification
(x+9
There seems to be a problem with your question - AEC does not create a triangle while ADE does.
As for finding x
Draw an imaginary line from C to D. 3^2+4^2=5^2, so take the square root to find CD=5. Now we know that CA is also 5. To find x, x^2+3^2=5^2, or x^2+9=25. Subtract 9 from both sides to get 16, and take the square root of both sides to get x=4.
