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blagie [28]
3 years ago
12

Plz I will give brainliest

Mathematics
2 answers:
Nimfa-mama [501]3 years ago
7 0

Answer:

20/21

Step-by-step explanation:

romanna [79]3 years ago
6 0
20/21
which is d :)
5/7 divided by 3/4 = 20/21
5/7 times 4/3 = 20/21
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Why might it be important to get a lower interest rate on a mortgage? a. lower monthly payment c. interest rate is not important
GarryVolchara [31]

Answer:

a

Step-by-step explanation:

8 0
2 years ago
How many 3/4s are in 3 2/4
MArishka [77]

Answer:

the answer is 3

Step-by-step explanation:

First change the whole number (3) to quaters or fraction

3x \frac{4}{4} = \frac{12}{4}

Now, add

\frac{2}{4} + \frac{12}{4} = \frac{14}{4}   Since, we have the same common denominator

now divide

14÷4 =3.5 = 3\frac{2}{4}

Therefore, there are 3 of 3/4 with a remainder of  \frac{2}{4} in 3 \frac{2}{4}.

7 0
3 years ago
Hint: If Angle XYZ (Exterior Angle Y) is 115, then Angle XYW (Interior Angle Y) must be 65 since they are supplementary angles.
RUDIKE [14]
Since all angles in a triangle are equal to 180 and you already have two angles you just have to subtract.
So, 180-(65 + 45)
Simplify = 180- 110
Equals = 70
4 0
2 years ago
The radioactive substance polonium-210, with a half-life of 138.39 days, is present in tobacco. Suppose that the soot in an ex-s
Ksju [112]

Answer:

16.07 milligrams

Step-by-step explanation:

From the question,

Using the formula of radioactive decay,

R/R' = 2ᵃ/ᵇ..................... Equation 1

Where R = Original mass of the polonium-210, R' = Final mass of polonium-210 after decaying, a = Total disintegration time, b = half life of polonium-210.

Make R' the subject of the equation

R' = R/(2ᵃ/ᵇ)................ Equation 2

Given: R = 100 milligrams, a = 1 years = 365 days, b = 138.39 days

Substitute these values into equation 2

R' = 100/(2³⁶⁵⁰⁰/¹³⁸³⁹)

R' = 100/(6.222)

R' = 16.07 milligrams of plonium-210

3 0
3 years ago
180 red marbles to 145 blue marbles
saul85 [17]

Answer:

325

Step-by-step explanation:

180+145 xDDDD

6 0
3 years ago
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