![\bf \qquad \qquad \textit{Future Value of an ordinary annuity} \\\\ A=pymnt\left[ \cfrac{\left( 1+\frac{r}{n} \right)^{nt}-1}{\frac{r}{n}} \right]](https://tex.z-dn.net/?f=%5Cbf%20%5Cqquad%20%5Cqquad%20%5Ctextit%7BFuture%20Value%20of%20an%20ordinary%20annuity%7D%0A%5C%5C%5C%5C%0AA%3Dpymnt%5Cleft%5B%20%5Ccfrac%7B%5Cleft%28%201%2B%5Cfrac%7Br%7D%7Bn%7D%20%5Cright%29%5E%7Bnt%7D-1%7D%7B%5Cfrac%7Br%7D%7Bn%7D%7D%20%5Cright%5D)

![\bf A=5280\left[ \cfrac{\left( 1+\frac{0.06}{1} \right)^{1\cdot 4}-1}{\frac{0.06}{1}} \right]](https://tex.z-dn.net/?f=%5Cbf%20A%3D5280%5Cleft%5B%20%5Ccfrac%7B%5Cleft%28%201%2B%5Cfrac%7B0.06%7D%7B1%7D%20%5Cright%29%5E%7B1%5Ccdot%20%204%7D-1%7D%7B%5Cfrac%7B0.06%7D%7B1%7D%7D%20%5Cright%5D)
Joe is making $485 payments monthly, but the amount gets interest on a yearly basis, not monthly, so the amount that yields interest is 485*12
also, keep in mind, we're assuming is compound interest, as opposed to simple interest
the distance between points is:
d = 7.8 units
d = root ((x2-x1) ^ 2 + (y2-y1) ^ 2)
The ordered pairs are:
(x1, y1) = (- 3, -2)
(x2, y2) = (2,4)
By applying the formula we have:
d = root ((2 - (- 3)) ^ 2 + (4 - (- 2)) ^ 2)
d = root (61)
d = 7.8
Answer: It should be D if im looking at this correctly
Step-by-step explanation:
Plain and simple
Answer:
-3 , 9
Step-by-step explanation:
Sum = - 6
Product = -27
Factors = 3, -9
x² - 6x-27 = 0
x² + 3x - 9x - 9*3 = 0
x(x + 3) - 9(x + 3) = 0
(x + 3) (x - 9) = 0
x +3 = 0 ; x - 9 = 0
x = - 3 ; x = 9
Solution: x = -3 , 9
This would be 12 - 12*cos(30) = 12 - 6

= 1.608 ft off the ground.