Answer:
C 61
Step-by-step explanation:
Answer:
The length of 
is;
D. 38 units
Step-by-step explanation:
The given parameters are;
The type of the given quadrilateral FGHI = Rectangle
The diagonals of the quadrilateral = and 
The length of IE = 3·x + 4
The length of EG = 5·x - 6
We have from segment addition postulate, = IE + EG
The properties of a rectangle includes;
1) Each diagonal bisects the other diagonal into two
Therefore, bisects , into two equal parts, from which we have;
IE = EG
= IE + EG
3·x + 4 = 5·x - 6
4 + 6 = 5·x - 3·x = 2·x
10 = 2·x
∴ x = 10/2 = 5
From which we have;
IE = 3·x + 4 = 3 × 5 + 4 = 19 units
EG = 5·x - 6 = 5 × 5 - 6 = 19 units
= IE + EG = 19 + 19 = 38 units
= 38 units
2) The lengths of the two diagonals are equal. Therefore, the length of segment is equal to the length of segment
Mathematically, we have;
= = 38 units
∴ = 38 units.
Substitute the given point (3, -2) in each condition
(i) y < -3; y ≤ (2/3)x - 4
-2 < -3 → False
Therefore, it is not a solution.
[Since the values of x and y must satisfy both the conditions, if one of them does not satisfy the condition then it is not necessary to check the other one.]
(ii) y > -3; y ≥ 2/3x - 4
-2 > -3 → True
y ≥ 2/3x - 4
-2 ≥ -2 → True
Therefore, it is a solution.
(iii) y < -3; y ≥ 2/3x - 4
-2 < -3 → False
Therefore, it is not a solution.
(iv) y > -2; y ≤ 2/3x - 4
-2 > -2 → False
Therefore, it is not a solution.
Thereofore, the system of linear inequalities having the point (3, -2) in its solution set is y > -3; y ≥ 2/3x - 4. Hope it helps you.
Answer:
12/7 bag of flour is required to make 3 batches of cookies
Step-by-step explanation:
From the question;
2/7 bag of flour makes 1/2 of a batch of cookies
x bag of flour will make 3 batches of cookies
Mathematically, we cross multiply
2/7 * 3 = 1/2 * x
6/7 = x/2
2 * 6 = 7 * x
12 = 7x
x = 12/7 bag of flour
Answer:
35.325 in³
Step-by-step explanation:
Since the base of a cylinder is a circle,
area of cylinder= πr²h
Radius, r
= diameter ÷2
= 3 ÷2
= 1.5 inches
Volume of can
= 3.14(1.5)²(5)
= 35.325 in³
