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julsineya [31]
3 years ago
8

What are some common acids and bases?

Advanced Placement (AP)
2 answers:
lutik1710 [3]3 years ago
6 0

Answer:

1. Acetic acid (CH3COOH): vinegar, acetate.

Acetylsalicylic acid (HOOCC6H4OOCCH3): aspirin.

Ascorbic acid (H2C6H6O6): vitamin C.

Carbonic acid (H2CO3): soft drinks, seltzer water.

Citric acid (C6H8O7): citrus fruits, artificial flavorings.

Hydrochloric acid (HCl): stomach acid.

2. an atom or molecule with a net electric charge due to the loss or gain of one or more electrons.

3. In the chemistry, acids and bases have been defined differently by three sets of theories. One is the Arrhenius definition, which revolves around the idea that acids are substances that ionize (break off) in an aqueous solution to produce hydrogen (H+) ions while bases produce hydroxide (OH-) ions in solution.

4. pH < 7.

Sour taste (though you should never use this characteristic to identify an acid in the lab)

Reacts with a metal to form hydrogen gas.

Increases the H+ concentration in water.

Donates H+ ions.

Turns blue litmus indicator red.

5. Bitter taste (opposed to sour taste of acids)

Slimy, or soapy feel on fingers (Slippery)

Many bases react with acids and precipitate salts.

Strong bases may react violently with acids. ...

Bases turn red litmus paper blue.

Bases are substances that contain metal oxides or hydroxides.

6. The salt comes from weathering and volcanic activity. The ocean formed very early on in Earth history, as soon as water comes into contact with rock then weathering processes start – these leach (dissolve) the soluble elements preferentially out of the rock (sodium, calcium, magnesium, potassium etc).

7. <u>Magnesium Sulfate</u>, It is the product of the chemical reaction between magnesium hydroxide and sulfuric acid. In natural medicine, Epsom salts can be used as a laxative. A solution of the salts is used in many homes as a soak for foot aches, bruises and sprains. Some people enjoy using the chemical in their bath water.

8. Salt is white, odorless and it has a salty taste.

All potassium (K), ammonium (NH4+) and sodium (Na) salts are soluble in water (H2O).

Nitrites, nitrates, and bicarbonates can be dissolved in water.

All metallic oxides, metallic carbonates, hydroxides, phosphates, and sulphides are insoluble in water.

9. pH is really a measure of the relative amount of free hydrogen and hydroxyl ions in the water. Water that has more free hydrogen ions is acidic, whereas water that has more free hydroxyl ions is basic. Since pH can be affected by chemicals in the water, pH is an important indicator of water that is changing chemically.

<em>Hope this helps!</em>

nataly862011 [7]3 years ago
5 0
The dude above me deserve a brainliest what the fak
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Explain in detail, how you solved the following problem: The first two terms of a sequence are 10 and 20. If each term after the
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Answer:

T_{2020} = 15

Explanation:

Given

T_1 = 10

T_2 = 20

Each term after the second term is the average of all of the preceding terms

Required:

Explain how to solve the 2020th term

Solve the 2020th term

Solving the 2020th term of a sequence using conventional method may be a little bit difficult but in questions like this, it's not.

The very first thing to do is to solve for the third term;

The value of the third term is the value of every other term after the second term of the sequence; So, what I'll do is that I'll assign the value of the third term to the 2020th term

<em>This is proved as follows;</em>

From the question, we have that "..... each term after the second term is the average of all of the preceding terms", in other words the MEAN

T_{n} = \frac{\sum T{k}}{n-1} ; where: k = 1 .... n -1

<em>Assume n = 3</em>

T_{3} = \frac{T_1 + T_2}{2}

<em>Multiply both sides by 2</em>

2 * T_{3} = \frac{T_1 + T_2}{2} * 2

2T_{3} = T_1 + T_2

<em>Assume n = 4</em>

T_{4} = \frac{T_1 + T_2 + T_3}{3}

T_{4} = \frac{(T_1 + T_2) + T_3}{3}

Substitute 2T_{3} = T_1 + T_2

T_{4} = \frac{2T_3 + T_3}{3}

T_{4} = \frac{3T_3}{3}

T_{4} = T_3

Assume n = 5

T_{5} = \frac{T_1 + T_2 + T_3 +T_4}{4}

T_{5} = \frac{(T_1 + T_2) + T_3 +(T_4)}{4}

Substitute 2T_{3} = T_1 + T_2 and T_{4} = T_3

T_{5} = \frac{2T_3 + T_3 +T_3}{4}

T_{5} = \frac{4T_3}{4}

T_{5} = \frac{(5-1)T_3}{5-1}

<em>Replace 5 with n</em>

T_{n} = \frac{(n-1)T_3}{n-1}

<em>(n-1) will definitely cancel out (n-1); So, we're left with</em>

T_{n} = T_3

Hence,

T_{2020} = T_3

Calculating T_3

T_{3} = \frac{10 + 20}{2}

T_{3} = \frac{30}{2}

T_{3} = 15

Recall that T_{2020} = T_3

T_{2020} = 15

3 0
3 years ago
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