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3 years ago

DO NOT SKIP NEED HELP

Mathematics

2 answers:

uysha [10]3 years ago

7 0

Answer:

i think blue

Step-by-step explanation:

Nina [5.8K]3 years ago

4 0

I think the answe is the blue box

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Can someone explain this to me?

jenyasd209 [6]

Answer:

Step-by-step explanation:

a). By applying tangent rule in the triangle,

tanθ = $\frac{\text{Opposite side}}{\text{Adjacent side}}=\frac{3}{4}$

θ = $\text{tan}^{-1}(\frac{3}{4})$

θ = 36.87°

Therefore, θ < 45°

b). By using cosine rule in this triangle,

cosθ = $\frac{\text{Adjacent side}}{\text{Hypotenuse}}=\frac{18}{18\sqrt{2}}$

cosθ = $\frac{1}{\sqrt{2}}$

θ = 45°

c). By using tangent rule,

tanθ = $\frac{\text{Opposite side}}{\text{Adjacent side}}=\frac{8}{2}$

θ = $\text{tan}^{-1}(4)$

θ = 75.96°

θ > 45°

4 0

3 years ago

The point (2, 1) is a solution to which of the following systems of equations?

Snezhnost [94]

$\huge\boxed{\left \{ {{x+y=3} \atop {3x-y=5}} \right.}$

We can solve this problem by testing the solution against each system of equations. We'll do this by substituting the point into each equation for each system.

<h2>System 1 - $\Large\textbf{X}$ </h2>

$\begin{array}{c|c}\textbf{First Equation}&\textbf{Second Equation}\\\cline{1-2}\begin{aligned}2x+y&=5\\2(2)+1&=5\\4+1&=5\\5&=5\\&\checkmark\end{aligned}&\begin{aligned}-2x+y&=2\\-2(2)+1&=2\\-4+1&=2\\-3&=2\\&\text{X}\end{aligned}\end{array}$

<h2>System 2 - $\Large\textbf{X}$ </h2>

$\begin{array}{c|c}\textbf{First Equation}&\textbf{Second Equation}\\\cline{1-2}\begin{aligned}-2x-y&=-5\\-2(2)-1&=-5\\-4-1&=-5\\-5&=-5\\&\checkmark\end{aligned}&\begin{aligned}2x-y&=2\\2(2)-1&=2\\4-1&=2\\3&=2\\&\text{X}\end{aligned}\end{array}$

<h2>System 3 - $\Large\textbf{X}$ </h2>

$\begin{array}{c|c}\textbf{First Equation}&\textbf{Second Equation}\\\cline{1-2}\begin{aligned}-x+y&=3\\-2+1&=3\\-1&=3\\&\text{X}\end{aligned}&\begin{aligned}-3x+y&=-5\\-3(2)+1&=-5\\-6+1&=-5\\-5&=-5\\&\checkmark\end{aligned}\end{array}$

<h2>System 4 - $\Large\checkmark$ </h2>

$\begin{array}{c|c}\textbf{First Equation}&\textbf{Second Equation}\\\cline{1-2}\begin{aligned}x+y&=3\\2+1&=3\\3&=3\\&\checkmark\end{aligned}&\begin{aligned}3x-y&=5\\3(2)-1&=5\\6-1&=5\\5&=5\\&\checkmark\end{aligned}\end{array}$