Check the picture below.
now, we have a triangle with all three sides, thus we can use Heron's Area Formula on the triangle.
![\bf \qquad \textit{Heron's area formula} \\\\ A=\sqrt{s(s-a)(s-b)(s-c)}\qquad \begin{cases} s=\frac{a+b+c}{2}\\[-0.5em] \hrulefill\\ a=10\\ b=26.695\\ c=22\\ s=29.3475 \end{cases} \\\\\\ A=\sqrt{29.3475(29.3475-10)(29.3475-26.695)(29.3475-22)} \\\\\\ A=\sqrt{29.3475(19.3475)(2.6525)(7.3475)}\implies A\approx \sqrt{11066.007} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill A\approx 105.195~\hfill](https://tex.z-dn.net/?f=%5Cbf%20%5Cqquad%20%5Ctextit%7BHeron%27s%20area%20formula%7D%20%5C%5C%5C%5C%20A%3D%5Csqrt%7Bs%28s-a%29%28s-b%29%28s-c%29%7D%5Cqquad%20%5Cbegin%7Bcases%7D%20s%3D%5Cfrac%7Ba%2Bb%2Bc%7D%7B2%7D%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20a%3D10%5C%5C%20b%3D26.695%5C%5C%20c%3D22%5C%5C%20s%3D29.3475%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5C%5C%20A%3D%5Csqrt%7B29.3475%2829.3475-10%29%2829.3475-26.695%29%2829.3475-22%29%7D%20%5C%5C%5C%5C%5C%5C%20A%3D%5Csqrt%7B29.3475%2819.3475%29%282.6525%29%287.3475%29%7D%5Cimplies%20A%5Capprox%20%5Csqrt%7B11066.007%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20~%5Chfill%20A%5Capprox%20105.195~%5Chfill)
Answer:
1: 3 ratio of the volume of the cone to the volume of the cylinder
Step-by-step explanation:
Volume of cone(V) is given by:

where, r is the radius and h is the height of the cone.
Volume of cylinder(V') is given by:

where, r' is the radius and h' is the height of the cylinder.
As per the statement:
A cylinder and a cone have congruent heights and radii.
⇒r = r' and h = h'
then;

⇒
Therefore, the ratio of the volume of the cone to the volume of the cylinder is, 1 : 3
Henry runs at a rate of seven miles an hour. I think you meant the second sentence to be 'Blake', because there is not attatched graph. They are both running at the same speed in this case.
I got this because 14 (miles ran by Henry) / 2 (hours ran) you get 7. This same equation is applied to (Blake?) 35 (miles ran by [Blake?]) / 5 (hours ran) also equals seven.
If you meant the second statement to be Blake, they are both running at the same speed, and x=7.
If you didn't, then there is not enough information to determine Blake's speed.
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