A room has an area of square meters and a perimeter of 32 meters what are the length and width of the room
1 answer:
Answer: Width = 6 meters
Length = 10 meters
Explanation:
Here's the complete question:
A room has an area of 60 square meters and a perimeter of 32 meters. What are the length and width of the room?
Area = Length × Width
Perimeter = 2(Length + Width)
Therefore,
L × W = 60 ....... i
2L + 2W = 32 ....... ii
From equation ii,
2L + 2W = 32
Divide through by 2
L + W = 16
L = 16 - W ........ iii
Put the value of L into equation i
L × W = 60
(16 - W) × W = 60
16W - W² = 60
W² - 16W + 60 = 0
W² - 10W - 6W + 60 = 0
W(W - 10) - 6(W - 10) = 0
(W - 6)(W - 10) = 0
Therefore,
W - 6 = 0
W = 0 + 6
W = 6
Width = 6 meters
Since Length = Area / Width
Length = 60/6
Length = 10 meters
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