Josiah and Chana travel at constant and different speeds.
- The point F indicates that after 25 seconds Josiah is 60 meters from the starting line but behind Chana
<h3>How can the what the the point <em>F </em>represent be known?</h3>
Josiah's head start = 10 meters from the start
Josiah's speed = 2 m/s
Chana's speed = 3 m/s
Expressing the distance traveled as an equation, we have;
D = d + s × t
Where;
D = The distance covered
d = The distance from the starting line the runner starts
s = The speed of the runner
t = The time spent running
For Josiah, we have;
D = 10 + 2•t (line <em>a</em>)
For Chana, we have;
D = 0 + 3•t = 3•t (line <em>b</em>)
The above equations are straight line equations.
The point <em>F </em>is on line <em>a</em>, which shows Josiah distance after 25 seconds which is 60 meters. The corresponding point on line <em>b</em>, Chana's distance after 25 minutes is 75 meters.
Therefore;
- The point <em>F </em>indicates that after 25 seconds Josiah is 60 meters from the starting line but behind Chana
Learn more about straight line equations here:
https://brainly.in/question/16254550
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The formula for the stopping distance in feet is
where 
= Speed of the car in miles per hour.
The stopping distance for the car traveling at 15 mph is
The stopping distance for the auto traveling at 15 mph is 
.
The stopping distance for the car traveling at 30 mph is
The stopping distance for the auto traveling at 30 mph is 
.
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Answer: 25 nickels
Step-by-step explanation:
EQUATIONS:
quantity: n + d = 63
value: 5n + 10d = 505
-------------------------
Divide thru the 2nd equation by 5 to get:
n + 2d = 101
----------------
Subtract that from the 1st equation:
-d = -38
d = 38 (# of dimes)
---------------
Substitute that into n+d=63 to solve for "n":
n + 38 = 63
n = 25 (# of nickels)
Answer:
Step-by-step explanation:
21.213
The answer should be -3, I can explain it if you want.
