Question

Find the distance between points l and m then find the distance between points l and n which distance is greater howmuch

Answer 1

Answer:

Following are the responses to the given question.

Step-by-step explanation:

In this question, the points values are missing which is why its solution can be defined as follows:

Let

$l= (7,-1) \\\\m=(-2, 4)\\\\n =(6,5)$

Formula:

$d=\sqrt{((x_2-x_1)^2+(y_2-y_1)^2)}$

For d1:

$x_1=7, y_1=-1, x_2=-2, y_2=4$

$d=\sqrt{((-2-7)^2+(4+1)^2)}$

  $=\sqrt{((-2-7)^2+(4+1)^2)}\\\\=\sqrt{((-9)^2+(5)^2)}\\\\=\sqrt{(81+25)}\\\\=\sqrt{(106)}\\\\=10.29$

For d2:

$x_1=7, y_1=-1, x_2=6, y_2=5$

$d=\sqrt{((6-7)^2+(5+1)^2)}$

  $=\sqrt{((-1)^2+(6)^2)}\\\\=\sqrt{(1+36)}\\\\=\sqrt{(37)}\\\\=6.08$

The first distance value is greater than the second distance value.