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mafiozo [28]
3 years ago
13

Which polynomial represents the sum below? 9x2 + x + 2 3x4 + 2x + 2​

Mathematics
1 answer:
baherus [9]3 years ago
3 0

Answer:

113x+2

Step-by-step explanation:

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There are twenty classes at each of two middle schools. The number of students in each class at each school is shown in the dot
tatuchka [14]

Answer:

There are about 2 more students in each class at Oak Middle School than at Poplar Middle School.

Step-by-step explanation:

The rest of the question is the attached figure.

It is required to compare between the mean number of students for the data in the plots.

The mean is sum of all data divided by the number of data.

The data set of Poplar Middle School:

20,20,20,21,21,21,21,21,22,22,22,22,22,22,22,23,23,23,23,24

So, The mean = 435/20 = 21.75

<u>The data set of Oak Middle School:</u>

20,21,21,22,22,23,23,23,23,24,24,24,25,25,26,26,27,27,28,29

So, The mean = 483/20 = 24.15

The difference in mean = 24.15 - 21.75 = 2.4

So, the correct statement is:

There are about 2 more students in each class at Oak Middle School than at Poplar Middle School.

7 0
3 years ago
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You were given 40 m of fencing to make a
DiKsa [7]
B) determine the maximum area of the garden
3 0
1 year ago
Which is the simplified form of the expression ((p squared) (q Superscript 5 Baseline)) Superscript negative 4 Baseline times ((
oksano4ka [1.4K]

Answer:

1/q^30 (startfraction 1 over q subscript 30 baseline end fraction)

Step-by-step explanation:

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5 0
3 years ago
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-22 - 7 answer the following integers! Show your work
konstantin123 [22]

-22-7=-22+(-7)=-22-7=-29

4 0
3 years ago
What is AE ? Enter your answer in the box. units Two segments A D and B C intersect at point E to form two triangles A B E and D
spin [16.1K]

Answer:

The length of AE is 20 units.

Step-by-step explanation:

Given two segments AD and BC intersect at point E to form two triangles ABE and DCE. Side AB is parallel to side DC. A E is labeled 2x+10. ED is labeled x+3. AB is 10 units long and DC is 4 units long.

we have to find the length of AE

AB||CD ⇒ ∠EAB=∠EDC and ∠EBA=∠ECD  

In ΔABE and ΔDCE

∠EAB=∠EDC      (∵Alternate angles)

∠EBA=∠ECD      (∵Alternate angles)

By AA similarity, ΔABE ≈ ΔDCE

therefore, \frac{AE}{ED}=\frac{AB}{CD}

⇒ \frac{2x+10}{x+3}=\frac{10}{4}

⇒ 8x+40=10x+30

⇒ x=5

Hence, AE=2x+10=2(5)+10=20 units

The length of AE is 20 units.

5 0
3 years ago
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