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qaws [65]
4 years ago
6

What is 5 + 2^3 divided by 4 - 2

Mathematics
1 answer:
MariettaO [177]4 years ago
7 0

Answer:

1. if its (5+2^3)/4-2 then its 6.5

2. if its just 5+2^3/4-2 then its 5

Step-by-step explanation:

1. (5+2^3)/4-2

   (5+8)/4-2

   (13)/4-2

    (13)/2

    6.5

2. 5+2^3/4-2

   5+8/4-2

  5+2-2

 7-2

 5

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4 years ago
12. Calculate the slope of the line that
zepelin [54]

Answer:

0

Step-by-step explanation:

m=y1-y2/x2-x1. Plug in your values. -7-(-7)/1-(-4). Simplifies to 0/5, or 0.

8 0
3 years ago
Fill in the table using this function rule y=10x+1
Mice21 [21]
Well you have no table for me to fill in but I can help you :)

Say that on the left side of your chart your x values are 1,2, and 3. 
just plug in those x values for x in the equation y=10x+1

so....
x        y
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1      y=10(1)+1 = y = 11
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2       y = 10(2)+1 = y = 21
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7 0
3 years ago
What times what equals -30 but also can be added together and equal -4
Step2247 [10]

Answer:

Step-by-step explanation:

xy=-30

y=-30/x

x+y=-4

x-30/x=-4

x²-30=-4x

x²+4x-30=0

x^2+4x-30=0\\x=\frac{-4\pm\sqrt{16+120} }{2} \\=\frac{-4\pm\sqrt{136} }{2} \\=-2\pm\sqrt{39} \\=-2+\sqrt{39} ,-2-\sqrt{39} \\y=\frac{-4}{-2+\sqrt{39} } ,\frac{4}{2+\sqrt{39} }correction write ~-30 ~in~place~of~-4~in~the~end

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Find the area of sector JKL. Enter your answer in terms of a fraction of π and rounded to the nearest hundredth.
Anna007 [38]

<u>Given</u>:

The radius of the circle is 4 cm.

The angle of the sector JKL is 135°

We need to determine the area of the sector JKL

<u>Area of the sector:</u>

The area of the sector can be determined using the formula,

A=\frac{\theta}{360^{\circ}} \times \pi r^{2}

Substituting \theta=135^{\circ} , r=4, we get;

A=\frac{135^{\circ}}{360^{\circ}} \times (3.14) (4)^{2}

A=\frac{3}{8} \times (3.14) (16)

A=\frac{150.72}{8}

A=18.84 \ cm^2

Thus, the area of the sector is 18.84 cm²

5 0
4 years ago
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